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3 years ago

Simplify the expression to a polynomial in standard form: (2x - 1)(-x^2+ 4x + 6)

Mathematics

1 answer:

Rom4ik [11]3 years ago

5 0

Answer:

$(2x - 1)( - {x}^{2} + 4x + 6) \\ = 2x \times - {x}^{2} + 2x \times4x + 2x \times 6 \\ - 1 \times - {x}^{2} - 1 \times 4x - 1 \times 6 \\ = - 2 {x}^{3} + 8 {x}^{2} + 12x + {x}^{2} - 4x - 6 \\ = - 2 {x}^{3} + 9 {x}^{2} - 8x - 6 \\ thank \: you$

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Are cells living? or not? 3 times 3 minus 6 (3x3-6) = ?

Arlecino [84]

Answer:

Yes, cells are living, because they make up living things, and can do what most living things are able to, like reproduce.

(3 x 3 - 6) = ?

First, multiply 3 x 3, which = 9

(9 - 6)

Then subtract 9 by 6, giving you 3.

So, :

(3 x 3 - 6) = 3

3 0

4 years ago

Someone gotta help me out, it’s geometry and I’m in a hurry and I can’t figure this out. Someone help pls :(

zalisa [80]

Equilateral Triangle: All 3 sides of a Triangle are equal in length

Isosceles Triangle: Two sides of Triangle are equal in length

Scalene: Triangle has different side lengths

So, for example, when you see Q1, you estimate the length of each side and think it is Scalene Triangle because all of its sides are of different length. (You can also use a ruler to find out the side lengths if it can be used for scale)

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Q6, when you look at the side lengths, you can tell it is an equilateral Triangle because all the sides are equal in length

You can try the rest and check for yourself. If you still have any doubts, you could ask me. I hope this information helps you.

4 0

2 years ago

Local versus absolute extrema. If you recall from single-variable calculus (calculus I), if a function has only one critical poi

stich3 [128]

Answer:

Step-by-step explanation:

Given that:

$f(x,y) = e^{3x} + y^3 - 3ye^x \\ \\ \implies \dfrac{\partial f}{\partial x} = 0 = 3e^{3x} -3y e^x = 0 \\ \\ e^{2x}= y \\ \\ \\ \implies \dfrac{\partial f}{\partial y } = 0 = 3y^2 -3e^x = 0 \\ \\ y^2 = e^x$

$\text{Now; to determine the critical point:}$ - $f_x = 0 ; \ \ \ \ \ f_y =0$

$\implies e^{2x} = y^4 = y \\ \\ \implies y = 0 \& y =1 \\ \\ since y \ne 0 , \ \ y = 1, \ \ x= 0\\\text{Hence, the only possible critical point= }(0,1)$

$\delta = f_xx, s = f_{xy}, t = f_{yy} \\ \\ . \ \ \ \ \ \ \ \ D = rt-s^2 \\ \\ i) Suppose D >0 ,\ \ \ r> 0 \ \text{then f is minima} \\ \\ ii) Suppose \ D >0 ,\ \ \ r< 0 \ \text{then f is mixima} \\ \\ iii) \text{Suppose D} < 0 \text{, then f is a saddle point} \\ \\ iv) Suppose \ D = 0 \ \ No \ conclusion$

$Thus \ at (0,1) \\ \\ \delta = f_{xx} = ge^{3x}\implies \delta (0,1) = 6 \\ \\ S = f_{xy} = -3e^x \\ \\ \implies S_{(0,1)} = -3 \\ \\ t = f_{yy} = 6y \\ \\$

$\implies t_{0,1} = 6$

$Now; D = rt - s^2 \\ \\ = (6)(6) -(-3)^2$

$= 36 - 9 \\ \\ = 27 > 0 \\ \\ r>0$

$\text{Hence, the critical point} \ (0,1) \ \text{appears to be the local minima}$

$\text{Suppose we chose x = 0 and y = -3.4} \\ \\ \text{Then, we have:} \\ \\ f(0,-3.4) = 1+ (-3.4)^3 + 3(3.4) \\ \\ = -28.104 < -1$

$\text{However, if f (0,1) = 1 +1 -3 = -1 \\ \\ f(0,-3.4) = -28.104} < -1} \\ \\ \text{This explains that} -1 \text{is not an absolute minimum value of f(x,y)}$

7 0

3 years ago

If our monthly income is $1,450 and your house payment is $1,125, what fraction of your monthly income must go to pay your house

hodyreva [135]

Answer:

1125/1450 or simplify it, 45/58

Step-by-step explanation:

1125/1450 or simplify it, 45/58

8 0

3 years ago

Which of the four is the answer?

Akimi4 [234]

Answer:

B. x^3(4x - 1)(4x + 1)

Step-by-step explanation:

16x^5 - x^3 =

= x^3(16x^2 - 1)

= x^3(4x - 1)(4x + 1)

7 0

3 years ago