Find the equation of a line that passes through the point (0, -2) and is parallel to a line that goes
1 answer:
Answer:
3x + 4y +8 = 0
Step-by-step explanation:
(X1,Y1) = (4,0)
(X2,Y2)=(0,3)
(X3,Y3)=(0, - 2)
Slope(m)=(Y2-Y1)/(X2-X1)
= (3-0)/(0-4)
= -3/4
Equation of the line,
Y-Y3 = m(X-X3)
Y-(-2)= (-3/4) × (X-0)
Y+2= (-3/4)X
Y+2= -3X/4
4(Y+2)= -3X
4Y+8= -3X
4Y+3X+8=0 is the required equation.
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