Question

Find the equation of a line that passes through the point (0, -2) and is parallel to a line that goes

Answer 1

Answer:

3x + 4y +8 = 0

Step-by-step explanation:

(X1,Y1) = (4,0)

(X2,Y2)=(0,3)

(X3,Y3)=(0, - 2)

Slope(m)=(Y2-Y1)/(X2-X1)

= (3-0)/(0-4)

= -3/4

Equation of the line,

Y-Y3 = m(X-X3)

Y-(-2)= (-3/4) × (X-0)

Y+2= (-3/4)X

Y+2= -3X/4

4(Y+2)= -3X

4Y+8= -3X

4Y+3X+8=0 is the required equation.