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3 years ago

(b) Eric removed 72 fish from his pond over a period of 9 days. He removed the same number of

Mathematics

1 answer:

Amanda [17]3 years ago

8 0

Answer:

-8

Step-by-step explanation:

72 ÷ 9 = 8

The fish are being taken out, so negative.

I hope this helps!

pls ❤ and mark brainliest pls!

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Write the word sentence as an equation. Then solve. Number 5.) 6.) 7.) and 8.)

Alecsey [184]

5.) x=2

6.) x=51

7.) x=44

8.) x=15

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3 years ago

A sample of 100 is drawn from a population with a proportion equal to 0.50. Determine the probability of observing between 43 an

diamong [38]

Answer:

The probability of observing between 43 and 64 successes=0.93132

Step-by-step explanation:

We are given that

n=100

p=0.50

We have to find the probability of observing between 43 and 64 successes.

Let X be the random variable which represent the success of population.

It follows binomial distribution .

Therefore,

Mean, $\mu=np=100\times 0.50=50$

Standard deviation , $\sigma=\sqrt{np(1-p)}$

$\sigma=\sqrt{100\times 0.50(1-0.50)]$

$\sigma=5$

Now,

$P(43\leq x\leq 64)=P(42.5\leq x\leq 64.5)$

$P(42.5\leq x\leq 64.5)=P(\frac{42.5-50}{5}\leq Z\leq \frac{64.5-50}{5})$

$=P(-1.5\leq Z\leq 2.9)$

$P(42.5\leq x\leq 64.5)=P(Z\leq 2.9)-P(Z\leq- 1.5)$

$P(42.5\leq x\leq 64.5)=0.99813-0.06681$

$P(43\leq x\leq 64)=0.93132$

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3 years ago

A particle is moving along the curve y= 4sqrt(5x+11) . As the particle passes through the point (5,24) , its -coordinate increas

kupik [55]

The rate of change of the distance from the particle to the origin at this instant is 3 units per second.

<h3>What is the rate of change?</h3>

The instantaneous rate of change is the rate of change at a particular instant.

A particle is moving along the curve

$y= 4\sqrt{5x+11} .$

The rate of change of y is given as:

dy / dx = 2

by differentiating both sides,

$\dfrac{dy}{dx} = 4\dfrac{1}{2\sqrt{5x+11} } 5\dfrac{dx}{dt} \\\\\dfrac{dy}{dx} = \dfrac{10}{\sqrt{5x+11} }\dfrac{dx}{dt}\\\\$

From the question, we have:

(x, y) = (5,24)

Substitute 5 for x and dy / dx = 2

$\dfrac{dy}{dx} = \dfrac{10}{\sqrt{5x+11} }\dfrac{dx}{dt}\\\\\\5= \dfrac{10}{\sqrt{5(5)+11} }\dfrac{dx}{dt}\\\\\\\sqrt{5(5)+11} = 2\dfrac{dx}{dt}\\\\\\\dfrac{dx}{dt} = 6/ 2 = 3$

Hence, the rate of change of the distance from the particle to the origin at this instant is 3 units per second.

Read more about rates of change at:

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2 years ago

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saul85 [17]

Answer:

C is the only correct answer

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2 years ago

Which experssion is equivalent to 4 to the power of 6 times 4 to the power of negative 8?

PilotLPTM [1.2K]

4 to the power of negative two beacause u add the exponents 6+ negative 8

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3 years ago