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2 years ago

(b) Eric removed 72 fish from his pond over a period of 9 days. He removed the same number of

Mathematics

1 answer:

Amanda [17]2 years ago

8 0

Answer:

-8

Step-by-step explanation:

72 ÷ 9 = 8

The fish are being taken out, so negative.

I hope this helps!

pls ❤ and mark brainliest pls!

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Between which pair of numbers is the exact product of 379 and 8?

AnnZ [28]

The product of 379 and 8 is 3,032.

It's between (any number less than 3,032) and (any number greater than 3,032).

I guess if this is an estimation exercise, you could say that it's between
(8 x 300) and (8 x 400), or 2,400 and 3,200.

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3 years ago

This is the last question which is the fifth one if you can PLS HELP

Trava [24]

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Read 2 more answers

Find all roots: x^3 + 7x^2 + 12x = 0 Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

Solution:

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

Therefore, the two roots are:

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

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3 years ago

Select the graph for the solution of the open sentence. Click until the correct graph appears. |x| > 4

nadezda [96]

Answer:

***********o o**************

<----------(-4)--------(-2)--------(0)--------(-2)----------(4)-------------->

x>4 or x<-4

Step-by-step explanation:

You are looking for numbers that give you a distance, x, greater than 4 from 0. That wouldn't be anything between -4 and 4 because these would all give you a distance less than 4 from 0. So the answer would be to shade everything greater than 4 while also shading everything less than -4.

Here is a number line <-----|-----|-----|-----|-----|-----|-----|-----|-->

-6 -4 -2 0 2 4 6 8

Let's think about this more which of these numbers on this number line would satisfy |x|>4?

Numbers inside the numbers -4 and 4.

Or the numbers on the outside.

Let's try the inside numbers:

-2,02

|-2|>4

2>4 is false which means -2 doesn't satisfy |x|>4

|0|>4

0>4 is false which means 0 doesn't satisfy |x|>4

|2|>4

2>4 is false which means 2 doesn't satisfy |x|>4

We could also try -4 and 4... but these will both give you a distance equal to 4 from 0. And we are looking for greater than.

|-4|>4

4>4 is false which mean -4 doesn't satisfy |x|>4

|4|>4

4>4 is false which means 4 doesn't satisfy |x|>4

Now let's try the numbers on the outside:

-6,6,8

|-6|>4

6>4 is true so -6 does satisfy |x|>4

|6|>4

6>4 is true so 6 does satisfy |x|>4

|8|>4

8>4 is true so 8 does satisfy |x|>4

So what I'm trying to do is convince you more that the only numbers that would satisfy |x|>4 are numbers outside the interval from -4 to 4.

So x>4 or x<-4.

On a number line the solution would look like this:

***********o o**************

<----------(-4)--------(-2)--------(0)--------(-2)----------(4)-------------->

We have holes at -4 and 4 to mean we do not include those numbers. We would have if the inequality read $|x| \ge 4$ . The line underneath this inequality means to include or equals. We do not want to include; we did not have the equal sign. The only difference between the two solutions would be to fill the holes if you $|x| \ge 4$ .

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3 years ago

Which equation represents a direct linear variation?

ivolga24 [154]

Y=1x because if you draw it on the line you’ll see the linear variation

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3 years ago