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LuckyWell [14K]
3 years ago
6

How do the 8 differ in 38108

Mathematics
1 answer:
kvasek [131]3 years ago
3 0
The left 8 represents 8000 units.
The right 8 represents 8 units.

Their placement in the number is used to signify the multiplier for the number of units they represent. That is why the number system is called a "place value number system." Each time the digit is moved left one place, its value increases by a factor of 10.
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Through: (-5, -4), slope = 0
madam [21]

Answer:

y + 4 = 0(x + 5)

y + 4 = 0

y = -4

Step-by-step explanation:

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3 years ago
A system has one each of two different types of components in joint operation. Let X and Y denote the random lengths of the live
RSB [31]

Answer:

The value of E(Y/X) is 2.

Step-by-step explanation:

As the complete question is not given, thus the complete question is found online and is attached herewith.

So the joint density function is given as

f(x,y)=\left \{ {{\dfrac{x}{8}e^{-\dfrac{x+y}{2}}    \,\,\,\,0 \leq x,0\leq y \atop {0}} \right.

So the marginal function for X is given as

f_x=\int\limits^{\infty}_0 {f(x,y)} \, dy\\f_x=\int\limits^{\infty}_0 \dfrac{x}{8}e^{-\frac{x+y}{2} }dy\\f_x=\int\limits^{\infty}_0 \dfrac{x}{8}e^{-\frac{x}{2}}e^{-\frac{y}{2} }dy\\f_x= \dfrac{x}{8}e^{-\frac{x}{2}}\int\limits^{\infty}_0e^{-\frac{y}{2} }dy\\f_x= \dfrac{x}{4}e^{-\frac{x}{2}}

Now

f(Y/X)=\dfrac{f(X,Y)}{f(X)}\\f(Y/X)=\dfrac{\dfrac{x}{8}e^{-\frac{x+y}{2} }}{\dfrac{x}{4}e^{-\frac{x}{2}}}\\f(Y/X)=\dfrac{1}{2}e^{-\frac{y}{2} }

Now the value of E(Y/X) is given as

E(Y/X)=\int\limits^{\infty}_0 {yf_{Y/X}} \, dy \\E(Y/X)=\int\limits^{\infty}_0 {y\dfrac{1}{2}e^{-\frac{y}{2} } }\, dy\\E(Y/X)=\dfrac{1}{2}\dfrac{\sqrt{2}}{(\dfrac{1}{2})^2}=2

So the value of E(Y/X) is 2.

3 0
3 years ago
On a quiz there are four-mulptiple choice questions worth 3 points each and two true/false questions worth 1 point​
Scilla [17]

Answer:

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Step-by-step explanation:

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2 years ago
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5 0
3 years ago
.Jim opened an account with $400. The account pays three percent quarterly. How much is in the account at the end of two years?
podryga [215]
We may have this planned like this:
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You will use the formula
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</span>I think this is the answer:) Hope it helps a lot
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