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Orlov [11]
3 years ago
15

Solve the problem please

Mathematics
1 answer:
Molodets [167]3 years ago
4 0

Answer:

x = 9±sqrt(7)

Step-by-step explanation:

3(x-9)^2 =21

Divide each side by 3

3/3(x-9)^2 =21/3

(x-9)^2 =7

Take the square root of each side

sqrt((x-9)^2) =±sqrt(7)

x-9 =±sqrt(7)

Add 9 to each side

x = 9±sqrt(7)

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Need help really bad
ehidna [41]

The translations are reflection across the x-axis, moved 3 units right, moved 5 units down

<u>Step-by-step explanation:</u>

f(x) = -(x-3)^{2} - 5

If we reflect a function across the x- axis then y = f(x) becomes y = -f(x)

So it becomes f(x) = -x^{2}

In the given function, there is a horizontal shift, moved 3 units right, then

it becomes, f(x) = -(x-3)^{2}

In this given function, there is a vertical downward shift of 5 units , so it becomes, that is moved 5 units down, then the function becomes,

f(x) = -(x-3)^{2} - 5

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3 years ago
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ArbitrLikvidat [17]
yes your answer does make sense. :)
7 0
3 years ago
Read 2 more answers
The sum of three consecutive integers is 72. Find the integers
dem82 [27]
Let's make an equation.
x+y+z=72
X will be the smallest number. Since they are consecutive, one number is one greater and the other is two greater. Let's make equation for y and z.
x+1=y; the middle number.
x+2=z; the greatest number.
Let's plug these in the equation.
x+x+1+x+2=72
Let's add like terms.
3x+3=72
Subtract 3.
3x=69
Now divide.
69÷3=23
So, the smallest number is 23. So, it must be set a. Let's check.
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4 0
3 years ago
1.05 x 10^4 in standard notation
vivado [14]

Answer:

10,500

Step-by-step explanation:

5 0
3 years ago
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Determine the sum of the first 33 terms of the following series:<br><br> −52+(−46)+(−40)+...
masya89 [10]

Answer:

1320

Step-by-step explanation:

Use the formula for sum of series, s(a) = n/2(2a + (n-1)d)

The terms increase by 6, so d is 6

a is the first term, -56

n is the terms you want to find, 33

Plug in the numbers, 33/2 (2(-56)+(32)6)

Simplify into 33(80)/2 and you get 1320

6 0
3 years ago
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