HELP PLEASE WILL MARK BRAINLIEST

Company A makes a large shipment to Company B. Company B can reject the shipment if they can conclude that the proportion of def

boyakko [2]

Answer:

$z=\frac{0.1475-0.1}{\sqrt{\frac{0.1(1-0.1)}{400}}}=3.17$

The p value for this case would be given by:

$p_v =P(z>3.17)=0.00076$

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 0.1 and then Company B can reject the shipment

Step-by-step explanation:

Information provided

n=400 represent the random sample taken

X=59 represent number of defectives from the company B

$\hat p=\frac{59}{400}=0.1475$ estimated proportion of defectives from the company B

$p_o=0.1$ is the value to verify

$\alpha=0.05$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to verify if the true proportion of defectives is higher than 0.1 then the system of hypothesis are.:

Null hypothesis: $p \leq 0.1$

Alternative hypothesis: $p > 0.1$

The statistic would be given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.1475-0.1}{\sqrt{\frac{0.1(1-0.1)}{400}}}=3.17$

The p value for this case would be given by:

$p_v =P(z>3.17)=0.00076$

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 0.1 and then Company B can reject the shipment

8 0

4 years ago

HELP ASAP IM BEING TIMED! THANKS

Genrish500 [490]

Answer:The second

Step-by-step explanation:

8 0

3 years ago

3.

Vitek1552 [10]

To solve this we are going to use the future value of annuity due formula: $FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n})^{kt}-1 }{ \frac{r}{n} } ]$
where
$FV$ is the future value
$P$ is the periodic deposit
$r$ is the interest rate in decimal form
$n$ is the number of times the interest is compounded per year
$k$ is the number of deposits per year

We know for our problem that $P=420$ and $t=15$ . To convert the interest rate to decimal form, we are going to divide the rate by 100%: $r= \frac{10}{100} =0.1$ . Since Ruben makes the deposits every 6 months, $k=2$ . The interest is compounded semiannually, so 2 times per year; therefore, $k=2$ .
Lets replace the values in our formula:

$FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n})^{kt}-1 }{ \frac{r}{n} } ]$
$FV=(1+ \frac{0.1}{2} )*420[ \frac{(1+ \frac{0.1}{2})^{(2)(15)}-1 }{ \frac{01}{2} } ]$
$FV=29299.53$

We can conclude that the correct answer is <span>$29,299.53</span>

8 0

4 years ago

A bucket was 7/10 full with water. After Vick washed the car, the bucket wad only 3/10 full. What fraction of the water in the b

Phoenix [80]

Hey there!

Vick had 7/10 bucket of water. . . .

She used some of the water and now has 3/10 left . . .

Subtracts the numbers 7 and 3 to solve this:

7 - 3 = 4 <----

The correct answer to your question should be 4/10 of a bucket.

Vick used 4/10 of the bucket to wash the car.

Hope this helps you.
Have a great day!

3 0

4 years ago

If you have 80 employees and you grow 116%, what was the amount of original employees?

Ganezh [65]

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Find the multiplier by diving the percentage by 100

116/100 = 1.16

Divide the number of employees by this:

80/1.16 = 68.9655...

There would be 68 employees.

Have A Nice Day ❤

Stay Brainly! ヅ

- Ally ✧

｡☆✼★ ━━━━━━━━━━━━━━ ☾

5 0

3 years ago