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malfutka [58]
3 years ago
12

A circle in the xy-plane is centered at (3, 0) and has a radius with endpoint (1, 8/3 ). Which answer choice is an equation of t

he circle?
Mathematics
1 answer:
gayaneshka [121]3 years ago
6 0

Answer: (x - 3)² + y² = \frac{100}{9}

<u>Step-by-step explanation:</u>

Circle Formula: (x - h)² + (y - k)² = r²  ; (h, k) is the center & r is the radius

Use the distance formula for (3, 0) and (1, \frac{8}{3})

r = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

r = \sqrt{(3-1)^{2}+(0-\frac{8}{3})^{2}}

r = \sqrt{(2)^{2}+(-\frac{8}{3})^{2}}

r = \sqrt{4+\frac{64}{9}}

r = \sqrt{\frac{36}{9}+\frac{64}{9}}

r = \sqrt{\frac{100}{9}}

r = \frac{10}{3}

****************************************************

Center (h, k) = (3, 0)   Radius (r) = \frac{10}{3}

(x - h)² + (y - k)² = r²

(x - 3)² + (y - 0)² = (\frac{10}{3})²

(x - 3)² + y² = \frac{100}{9}

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