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3 years ago

A percent measures a rate

Mathematics

2 answers:

OlgaM077 [116]3 years ago

7 0

answer = no it does not measure a rate

Gemiola [76]3 years ago

6 0

Answer:

Step-by-step explanation:

Percent is just a number out of 100

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Part A: Solve −np − 70 < 40 for n.

Trava [24]

Solve for n the first can be like:-NP<40+70. -NP<110 the second one can be like : 4w-7k =28. solve for k and then, -7k=28-4w divide both sides by -7 that equal to k =-4-4w

5 0

3 years ago

Pls help! I need the slope, I can plot the points!

Karolina [17]

I think it’s b to be honest with you

4 0

3 years ago

Read 2 more answers

Micheal buys two bags or chips and three boxes of pretzels for $5.13 . He then buys another bag of chips and 2 boxes of pretzels

trapecia [35]

Answer:

So a bag of chip costs $2.39

Step-by-step explanation:

Let x = cost of a bag of chip

Let y = cost of a box of pretzel

Micheal buys two bags of chips and three boxes of pretzels for $5.13

This means

2x + 3y = 5.13 - - - - - - - - - -1

He then buys another bag of chips and 2 boxes of pretzels for $3.09

This means

x + 2y = 3.09 - - - - - - - - - - - -2

Solving equation 1 and equation 2 simultaneously and using the elimination method,

Multiply equation 1 by 1 and equation 2 by 2

2x + 3y = 5.13

2x + 6y = 6.18

Subtracting,

-3y = -1.05

y = -1.05/-3= $0.35

Put y= 0.35 in equation, x + 2y = 3.09

x + 2(0.35)= 3.09

x + 0.7= 3.09

x = 3.09-0.7 = $ 2.39

So a bag of chip costs $2.39

5 0

3 years ago

Factor 15 + 50.<br> 5(10 + 3)<br> 5(3 + 10)<br> 3(5 + 25)<br> 10(5 + 5)

Agata [3.3K]

Answer:

Step-by-step explanation:

So we have the expression:

$15+50$

Since 5 goes into both 15 and 50, we can factor out a 5. First, rewrite the numbers as:

$5(3)+5(10)$

Factor out the 5:

$=5(3+10)$

So, our answer is B

And we're done!

8 0

3 years ago

A student wanted to construct a 95% confidence interval for the mean age of students in her statistics class. She randomly selec

VMariaS [17]

Answer:

$19.1-3.355\frac{1.5}{\sqrt{9}}=17.42$

$19.1+3.355\frac{1.5}{\sqrt{9}}=20.78$

And the best option would be:

C. [17.42,20.78]

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=19.1$ represent the sample mean

$\mu$ population mean (variable of interest)

s=1.5 represent the sample standard deviation

n=9 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=9-1=8$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,8)".And we see that $t_{\alpha/2}=$

Now we have everything in order to replace into formula (1):

$19.1-3.355\frac{1.5}{\sqrt{9}}=17.42$

$19.1+3.355\frac{1.5}{\sqrt{9}}=20.78$

And the best option would be:

C. [17.42,20.78]

5 0

3 years ago