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galben [10]
3 years ago
12

Write a polynomial in standard form with the zeros –4 0 1 and 4

Mathematics
1 answer:
Tasya [4]3 years ago
6 0

Step-by-step explanation:

Hi there!

Zero of the polynomial is the value of "X" that gives final answer as zero.

<em>So, as the polynomial in the second gives zero every time when we keep the zero which are given in the question. It is the answer.</em>

Check:

• x⁴ - x³ - 16x² + 16x

  • (-4)

Keep the value -4 as the value of X in polynomial.

= (-4)⁴-(-4)³ -16*(-4)²+16*(-4)

= 256+64-256-64

= 0

  • 0

Keep the value 0 as the value of X in polynomial.

= (0)⁴-(0)³ -16*(0)²+16*(0)

= 0-0-0+0

= 0

  • 1

Keep the value 1 as the value of X in polynomial.

= (1)⁴-(1)³ -16*(1)²+16*(1)

= 1-1-16+16

= 0

  • 4

Keep the value 4 as the value of X in polynomial.

= (4)⁴-(4)³ -16*(4)²+16*(4)

= 256 - 64-256+64

= 0

Therefore, the correct answer is option B.

<u>Hope it helps!</u>

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A simple random sample of 90 is drawn from a normally distributed population, and the mean is found to be 138, with a standard d
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The 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

<h3>
How to find the confidence interval for population mean from large samples (sample size > 30)?</h3>

Suppose that we have:

  • Sample size n > 30
  • Sample mean = \overline{x}
  • Sample standard deviation = s
  • Population standard deviation = \sigma
  • Level of significance = \alpha

Then the confidence interval is obtained as

  • Case 1: Population standard deviation is known

\overline{x} \pm Z_{\alpha /2}\dfrac{\sigma}{\sqrt{n}}

  • Case 2: Population standard deviation is unknown.

\overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}

For this case, we're given that:

  • Sample size n = 90 > 30
  • Sample mean = \overline{x} = 138
  • Sample standard deviation = s = 34
  • Level of significance = \alpha = 100% - confidence = 100% - 90% = 10% = 0.1 (converted percent to decimal).

At this level of significance, the critical value of Z is: Z_{0.1/2} = ±1.645

Thus, we get:

CI = \overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}\\CI = 138 \pm 1.645\times \dfrac{34}{\sqrt{90}}\\\\CI \approx 138 \pm 5.896\\CI \approx [138 - 5.896, 138 + 5.896]\\CI \approx [132.104, 143.896] \approx [130.10, 143.90]

Thus, the 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

Learn more about confidence interval for population mean from large samples here:

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