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Tom [10]
2 years ago
10

rick jogged the same distance on tuesday snd friday, and 8 miles on sunday for a total of 20 miles for the week. solve to find t

he distance rick jogged on tuesday and friday
Mathematics
1 answer:
saveliy_v [14]2 years ago
3 0

Ricky jogged 6 miles on tuesday and 6 miles on friday

<em><u>Solution:</u></em>

Given that,

Rick jogged the same distance on tuesday and friday

Let "x" be the distance jooged on each tuesday and friday

He also jogged for 8 miles on sunday

Total of 20 miles for the week

Therefore, we frame a equation as,

total distance jogged = miles jogged on tuesday + miles jogged on friday + miles jogged on sunday

20 = x + x + 8

20 = 2x + 8

2x = 20 - 8

2x = 12

x = 6

Thus Ricky jogged 6 miles on tuesday and 6 miles on friday

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Answer:

Points are at (3.25, 3.2), (3.5, 3.0), (3.5, 2.9), (3.25), (3.0), (2.5, 3.0), (4, 3.0), (4, 3.1), (3.5, 3.1), (3.25, 3.1), (3.5, 3.0), (3.5, 3.0), (4, 3.1), (3, 3.0), (3.5, 3.1), (2.25, 2.9), (2.5, 2.8)

Step-by-step explanation:

Given the data :

Column 1 High School G P A:

3.25, 3.5, 3.5, 3.25, 2.5, 4, 4, 3.5, 3.25, 3.5, 3.5, 4, 3, 3.5, 2.25, 2.5

Column 2 College G P A :

3.2, 3.0, 2.9, 3.0, 3.0, 3.0, 3.1, 3.1, 3.1, 3.0, 3.0, 3.1, 3.0, 3.1, 2.9, 2.8.

To prepare a scatter plot ; with x - axis plotted against y - axis ;

Each point on the x - axis is paired with a corresponding point on the y - axis ;

With high school GPA on the x axis and College GPA on y :

Values are paired in the form:

(X1, Y1),.. (Xn, Yn)

(3.25, 3.2)

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2 years ago
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x/5)+12=16

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Hope this helps! Have a nice day!

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(9CQ) Find the distance from the balloon to the soccer fields.
almond37 [142]

Answer:

The distance from the balloon to the soccer fields = 3.6 miles ⇒ answer (b)

Step-by-step explanation:

* Let the hot air balloon  at point A , the soccer fields

  at point B and the football field at point C

∵ The measure of the angle of depression to the

   soccer fields is 20° 15'

∴ The measure of angle B = 20° 15'

∵ The measure of the angle of depression to the

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∴ The measure of angle C = 62° 30'

∵ The sum of measures of the interior angles of any triangle = 180°

∴ The measure of angle A = 180 - (20° 15' + 62° 30') = 97° 15'

* The distance between the balloon and the soccer field

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∵ a/sin(A) = b/sin(B) = c/sin(C)

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∵ AB = c ⇒ opposite to angle C

∵ The distance between the two fields = 4 miles

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∵ BC = a ⇒ opposite to angle A

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∴ c = (4 × sin(62° 30')) ÷ sin(97° 15')

∴ c = 3.6 miles

∴ The distance from the balloon to the soccer fields = 3.6 miles

   answer (b)

4 0
3 years ago
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