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2 years ago

There are 25 children in the class 3/5 of the children in the class are boys. how many girls are their?

2 answers:

8 0

There are 10 girls in the class. You want to multiply (3/5)x25, once product is found, you subtract it from 25, the product is 15, so 25-15=10girls

Harman [31]2 years ago

4 0

Answer:

10 girls

Step-by-step explanation:

If 3/5 of the class consists of boys, (5/5 - 3/5 = 2/5) : 2/5 are girls

3/5 x 25 = 15

2/5 (girls) = 25 - 15

Therefore, 10 girls in total

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Evaluate −4x − y + 4 when x = −14 and y = 3

miskamm [114]

Answer:

Step-by-step explanation:

-4x-y+4

plug in the numbers for the letters

-4(-14)-3+4

multiply -4(-14)= 56

56-3+4

subtract 3

53+4

add 4

5 0

2 years ago

Read 2 more answers

A student has received the following test scores: 71%, 89%, 72%,

lidiya [134]

Answer: 81%

Step-by-step explanation:

From the question, we are informed that a student received the following test scores: 71%, 89%, 72%,

84% and 83% in 5 tests and the student wants to maintain an average of 80%.

The lowest score/grade they can receive on the next test to maintain at least an 80% average first thus:

First, to make it easy we can remove the percent sign. Then we multiply 80 by 6 since we're calculating for 6 tests scores. This will be:

= 80 × 6

= 480

We then add all the 5 test scores. This will be:

= 71 + 89 + 72 + 84 + 83

= 399

We then subtract the values gotten. This will be:

= 480 - 399

= 81

This means the student must get at least 81%

5 0

3 years ago

Solve for x: 2 - 6 = 0 X = Help plz

antiseptic1488 [7]

Answer:

because when you subtract 6 from 6 you get 0

6 - 6 = 0

8 0

3 years ago

19. which one of the following is not equal to the rest? a 2% of 150 b. % of 400 b 3 c. 6% of 60 d. 69 of 50

Irina18 [472]

Answer:

i think it's c

Step-by-step explanation:

a. 2/100 × 150= 3. b. 100×400=40000. c. 6/100 ×60= 1.2 ×3=3.6. d. 69×50=3400 so answer c.

5 0

2 years ago

Factor over the complex numbers: 36x2 + 9.

ludmilkaskok [199]

$36x^2+9=(6x)^2-(-9)=(6x)^2-(-3^2)\\\\=(6x)^2-(3i)^2=(6x-3i)(6x+3i)\\\\\text{Used:}\\a^2-b^2=(a-b)(a+b)\\\\i^2=-1$

4 0

3 years ago