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creativ13 [48]
3 years ago
13

Find the sum : (i) 23123, 11001 and 21302 (iii) 21031, 12301 and 32211 (v) 21003, 12346 and 21220 (ii) 32101, 12301 and 1032 (iv

) 301242, 123310 and 10002
Mathematics
2 answers:
Valentin [98]3 years ago
7 0

Answer:

  • (i) 23123 +  11001 + 21302 =  55426
  • (ii) 32101 + 12301 + 1032 = 45434
  • (iii) 21031 + 12301 + 32211 =  65543
  • (iv) 301242 + 123310 + 10002 = 434554
  • (v) 21003 + 12346 + 21220 = 54569
Akimi4 [234]3 years ago
3 0

1:-

\\ \sf\longmapsto 23123+11001+21302

\\ \sf\longmapsto 55426

2:-

\\ \sf\longmapsto 21031+12301+32211

\\ \sf\longmapsto 65543

3:-

\\ \sf\longmapsto 21003+12346+21220

\\ \sf\longmapsto 54569

4:-

\\ \sf\longmapsto 32101+12301+1032

\\ \sf\longmapsto 45434

5:-

\\ \sf\longmapsto 301242+123310+10002

\\ \sf\longmapsto 434554

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