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3 years ago

Please help basic Geomerty question!

Mathematics

1 answer:

guapka [62]3 years ago

6 0

Answer:

Point B :(6, 7)

Step-by-step explanation:

Point B:(x, y)

1= - 4+x/2

2= - 4+x

x=6

7.5= 8+y/2

15= 8+y

y=7

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∠x and ∠y are supplementary angles ∠y measures 142 what is the measure of x

mr_godi [17]

Supplementary angles add up to 180

⇒ ∠x + ∠y = 180

∠x + ∠y = 180

∠x + 142 = 180

∠x = 180 - 142 = 38°

Answer: x = 38°

6 0

4 years ago

Trigonometry problem

IgorC [24]

Answer:

The values are x = 0° or x = 60°

Step-by-step explanation:

Given:

$\cos x + \frac{1}{\sqrt{3} }\times \sin x = 1$

Let it be in the form of

$a\cos x + b\sin x = 1$ such that

a = 1

$b=\frac{1}{\sqrt{3} }$

We have

$\sqrt{(a^{2}+b^{2} )}=\sqrt{(1^{2}+(\frac{1}{\sqrt{3} }) ^{2} )}\\=\sqrt{\frac{4}{3}}\\=\frac{2}{\sqrt{3} }$

Now, Dividing both the side by $\frac{2}{\sqrt{3} }$ we get

$\frac{\sqrt{3} }{2}\cos x + \frac{1}{2}\sin x =\frac{\sqrt{3} }{2}\\$

We Know

$\sin 60 =\frac{\sqrt{3} }{2}\\and\\\cos 60 = \frac{1}{2}$

Now by replacing with above values we get

$\sin 60\times \cos x + \cos 60\times \sin x = \frac{\sqrt{3} }{2}\\$

Also we have formula

$\sin A\times \cos B + \cos A\times \sin B = \sin (A+B)$

By applying the above Formula we get

$\sin (60+x)=\frac{\sqrt{3} }{2}\\$

Also ,

$\sin (60)=\frac{\sqrt{3} }{2}\\and\\\sin (120)=\frac{\sqrt{3} }{2}$

Comparing we get

60 + x = 60 or 60 + x = 120

∴ x = 0° ∴ x = 120 - 60 = 60°

Therefore, the values are x = 0° or x = 60° i.e between 0° to 360°

5 0

3 years ago

Find the value of x.

HACTEHA [7]

Answer:

what

Step-by-step explanation:

sure?

5 0

3 years ago

Help me on this . It’s important

bixtya [17]

Answer:

The answer is 16.

Step-by-step explanation:

6 x 3 = 18

18 - 2 =16

5 0

3 years ago

Read 2 more answers

Point P(−5, 2) is translated using the rule (x+3, y−1).<br><br> What is the x-coordinate of P' ?

kirill115 [55]

The x coordinate of P' is -2

4 0

4 years ago