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mezya [45]
3 years ago
7

Solve for z −4z + 31 ≥ 17z + 23

Mathematics
2 answers:
mojhsa [17]3 years ago
6 0

Answer:

z ≤ 8/21

​

Step-by-step explanation:

Flip the inequality sign since you are multiplying by a negative number

 21z-8  ≤ 0

1.2    Divide both sides by  21  

 z-(8/21)  ≤ 0

Add  8/21  to both sides

z ≤ 8/21

Natali [406]3 years ago
3 0

z  \leqslant  \frac{8}{21}

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The amount of decreased divided by the original amount equals the ___of decreased
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Which equations are true for x = –2 and x = 2? Select two options x2 – 4 = 0 x2 = –4 3x2 + 12 = 0 4x2 = 16 2(x – 2)2 = 0
Svetllana [295]

The equation x^{2} -4=0~~and~~4x^2=16 are true for  x = -2 and x = 2.

The given equations are given as:

x^2-4=0\\\\x^2=-4\\\\3x^2+12=0\\\\4x^2=16\\\\2(x-2)^2=0

We need to select two equations that are true for x = -2 and x = 2.

<h3>What are the solutions to an equation ?</h3>

The solutions of an equation are the values that satisfy the given equation or make the equation true when substituted for unknowns in the equations.

Example:

x - 2 = 2

Here the solution for x - 2 = 2 is 4 because x = 4 will make the equation true.

4 - 2 = 2

2 = 2

Let's find the solutions for each equation.

1.

x^2 - 4=0

x^{2} = 4

x = \sqrt{4} = ± 2

x = = 2 and x = -2

2.

x^2 =-4

x = \sqrt{-4}

x = \sqrt{-1 \times 4} = \sqrt{-1}\times\sqrt{4}

x = ± 2 \sqrt{-1}

x = 2i and x = -2i         where i = \sqrt{-1}

3.

3x^{2} + 12  = 0

x^{2} = -12 / 3 = -4

x = \sqrt{-1} \sqrt{4}

x = ± 2\sqrt{-1}

x = 2i and x = -2i

4.

4x^{2} = 16

x^{2} = 16 / 4

x^{2} = 4

x = \sqrt{4}

x = ±2

x = 2 and x = -2

5.

2(x-2)^2 = 0

(x-2)^2 = 0

x - 2 = 0

x = 2.

Thus the equation x^{2} -4=0~~and~~4x^2=16 have solutions x = -2 and x = 2.

Learn more about solutions of equations here:

brainly.com/question/14506845

#SPJ1

4 0
2 years ago
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