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kow [346]
3 years ago
12

Which of the following is a correct tangent ratio for the figure?

Mathematics
1 answer:
Ludmilka [50]3 years ago
3 0

Answer:

tan 76 = 24/8

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp /adj

tan 76 = 24/8

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Solve -2p + 10p = 7p for p.
BartSMP [9]

Answer: P = 0

Step-by-step explanation:

Solve for p by simplifying both sides of the equation, the isolating the variable.

-2p + 10p = 7p, P will equal 0.

***If you found my answer helpful, please give me the brainliest. :) ***

8 0
3 years ago
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I will give brainlist please someone help!!!​
Cerrena [4.2K]

Answer:

x = 6

Step-by-step explanation:

Alternate angles are congruent.

7x - 9 = 3x + 15               {Subtract 3x form both sides}

7x - 3x -9 = 15

      4x - 9=15            {Add 9 to both sides}

           4x = 15+9

           4x = 24

           x = 24/4

x = 6

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3 years ago
The function g is related to one of the parent function g(x)=-(x-2)^3
Svetllana [295]

Answer:

(2,0)

Step-by-step explanation:

4 0
2 years ago
Please Show Work.
s344n2d4d5 [400]

Answer:

\huge\boxed{x=17}

Step-by-step explanation:

It's important to note that when two angles create a straight line, they are supplementary.

This means their angle measures add up to 180° since a 180° angle is a straight line.

Since we know the measures of both angles in equation form, we can add them together and have them equal 180 to solve for x.

(5x-18) + (4x+45) = 180

Combine like terms:

9x + 27 = 180

Subtract 27 from both sides:

9x = 153

Divide both sides by 9:

x = 17

So x = 17.

Hope this helped!

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3 years ago
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9.

\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\1. SJ=FJ&\text{1. Given}\\2.KS=3, KF=3&\text{2. Given}\\3.KS=KF&\text{3. Transitive Property}\\4.\angle SJK = \angle FJK&\text{4. Congruent sides }\\5.JK=JK&\text{5. Reflexive Property}\\6. \triangle SJK \cong \triangle FJK&\text{6. Side-Angle-Side Theorem}\\\end{array}


10.

\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\1.MA || TH&\text{1. Given}\\2. \angle MAX \cong \angle THX&\text{2. Alternate Interior Angles}\\ \text{3. x is midpoint of AH}&\text{3. Given}\\4.AX \cong HX&\text{4. Deefinition of midpoint}\\5. \angle AXM \cong \angle HXT&\text{5. Vertical angles}\\6. \triangle MAX \cong \triangle THX&\text{Angle-Side-Angle Theorem}\\\end{array}

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3 years ago
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