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zimovet [89]
3 years ago
15

3+4 + (-5) = I’m learning about subtract integers

Mathematics
1 answer:
sleet_krkn [62]3 years ago
8 0

Answer:

2

Step-by-step explanation:

3+4+(-5)=7+(-5)=7-5=2

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My sister needs help lol. (She is young)
scZoUnD [109]

Answer:

The answer is A-2

Step-by-step explanation:

because half of 4 (Which is the width of the flower garden) is 2 (Which would be the width of the Vegetable garden.

4 0
3 years ago
PLEASE HELP
Viefleur [7K]
7x²=9+x
so
for
0=ax²+bx+c

x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}
so

7x²=9+x
mins 9 from both sides and minus x
7x²-1x-9=0
a=7
b=-1
c=-9


x=\frac{-(-1)+/-\sqrt{(-1)^2-4(7)(-9)}}{2(7)}
x=\frac{1+/-\sqrt{(-1)^2+4(7)(9)}}{2(7)}
so the 4th one
4 0
3 years ago
A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1
Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given  : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find :  transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then   Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

4 0
3 years ago
Read 2 more answers
What is the answer to 6x^3+2x-18=0
OlgaM077 [116]

Answer:

around 1.3

Step-by-step explanation:

3 0
3 years ago
Consider the following hypothesis test H0 p 20 Ha p 20 A sample of 400 provided a sample proportion p 175 a Compute the value of
Bogdan [553]

Answer:

a) -1.25

b) 0.2112

c) -1.96

Step-by-step explanation:

Data provided in the question:

Sample size, n = 400

H0 : p = 20

\bar{p} = 175

Now,

a) The test statistic is  given as:

Z = \frac{(\bar{p}-p)}{\sqrt{\frac{p(1-p)}{n}}}

on substituting the respective values, we get

Z = \frac{(0.175-0.2)}{\sqrt{\frac{0.2\times0.8}{400}}}

= -1.25

b) The p-value = 2 × P(Z <-1.25)

Now from the standard normal table

P(Z <-1.25) = 10.56% = 0.1056

Thus,

p-value = 2 × 1056 = 0.2112

c) for a = 0.05,

the critical value is Z_{\frac{a}{2}}=Z_{\frac{0.05}{2}} i.e Z_{0.025}

Now from standard normal table

Z_{0.025} = -1.96

3 0
3 years ago
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