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konstantin123 [22]
3 years ago
10

point k is between j and l. if jk = x^2 - 4x , kl = 3x - 2 and jl = 28 write and solve an equation to find the lengths of jk and

kl
Mathematics
1 answer:
inn [45]3 years ago
7 0

Answer:

JK=12

KI=16

Step-by-step explanation:

K\in\ [JI]\ \Rightarrow\ |JK|+| KI |=|KI|\\\\x^2-4x+3x-2=28\\\\\Longleftrightarrow\ x^2-x-30=0\\\\\\\Longleftrightarrow\ x^2+5x-6x-30=0\\\\\\\Longleftrightarrow\ x(x+5)-6(x+5)=0\\\\\\\Longleftrightarrow\ (x+5)(x-6)=0\\\\x=-5\ (excluded)\ or\x=6\\\\\\\Longleftrightarrow\ \\|JK|=x^2-4x=6^2-4*6=36-24=12\\|KI|=3x-2=3*6-2=18-2=16\\\\Proof: 12+16=28\\

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Answer:

A)60°

Step-by-step explanation:

a straight line is 180° then

if a line bisect it in to a half it become 90°

then

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this means 150°-90°=60°

8 0
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Which of the following are solution to the inequality below -4w - 2 &lt; -38
FromTheMoon [43]

Answer:

w > 9

Step-by-step explanation:

Solve the inequality by using inverse operations.

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8 0
3 years ago
8.45 At some point in the season, the Unicorns had won 60% of their basketball games. After that point, they won 8 more games an
ololo11 [35]

Answer:

The total number of games won by Unicorn is 40.

Step-by-step explanation:

  • We are given with a word problem
  • We are asked to find the number of unicorns played during the season
  • We can do this in two steps

         Step 1: Finding the win percentage

         Step 2: Finding the number of unicorns played during the season

Step 1 of 2

Let the number of games played by unicorn be x.The unicorn won 60% of the first x-10 games That is $\frac{60}{100} \times(x-10)$

Combining the 8 games we get,

$$\begin{gathered}\frac{60}{100}(x-10)+8=\frac{60}{100} \times x-\frac{60}{100} \times 10+8 \\0.6 x-6+8=0.6 x+2\end{gathered}$$

Step 2 of 2

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That is $\frac{65}{100} \times x=0.65 x$

Equating both the equation gives

$$\begin{gathered}0.6 x+2=0.65 x \\2=0.65 x-0.6 x \\2=0.05 x \\\frac{2}{0.05}=x \\40=x\end{gathered}$$

5 0
2 years ago
Please help thank you
REY [17]

Answer:

True

True

False

7 0
3 years ago
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