Answer:
Step-by-step explanation:
Average speed = distance/time
Trip to dry dock
Let x be the velocity
Time = 2hours
Distance = average speed ×time
Distance = x×2
Distance = 2x
Return trip
Velocity = x-5 (5 miles per hour faster on the trip there than on the return trip)
Time = 3hrs
Distance = 3(x-5)
Since the distance is the same both to and fro;
2x = 3(x-5)
2x = 3x -15
2x-3x = -15
-x = 15
x = 15
Hence the aircraft carrier's average speed on the outbound trip is 15miles/hour
The 7 in the hundreds place would represent 700 <span />
Answer:
x = 2.8
y = 2
Step-by-step explanation:
Reference angle = 45°
Opposite = 2
Hypotenuse = x
Adjacent = y
✔️To find x, apply the trigonometric function SOH:
Sin 45 = Opp/Hyp
Sin 45 = 2/x
x*Sin 45 = 2
x = 2/Sin 45
x = 2.82842712 ≈ 2.8 (nearest tenth)
✔️To find y, apply the trigonometric function TOA:
Tan 45 = Opp/Adj
Tan 45 = 2/y
y*Tan 45 = 2
y = 2/Tan 45
y = 2
C, the graph is not a straight line, meaning that for every x value, a definite y value is not present. The graph is an exponential graph, meaning that for every x value, the y value is related to the power of x.
The answer is 24w - 16u + 48