Answer:
Length of XM is 5.5 units.
Step-by-step explanation:
Given △XYZ where MZ is the angle bisector of ∠YZX . we have to find the length of XM.
A triangle with vertices X, Y, and Z. Side XZ is base. A line segment drawn from Z to M bisects ∠YZX into two parts ∠YZM and ∠XZM.
YZ=7 units, XZ=11 units and YM=3.5 units
By angle bisector theorem which states that an angle bisector of an angle divides the opposite side in two segments that are proportional to the another two sides of the triangle.
Hence, 
⇒ 
⇒ MX=5.5 units.
Hence, length of XM is 5.5 units.
Here u go, u replace x by the number
An=a1r^(n-1)
given
a5=1/24
a10=1/768
we know that
a5=1/24=a1r^(5-1) and
a10=1/768=a1r^(10-1)
so
1/24=a1r^4
1/768=a1r^9
(a1r^9)/(a1r^4)=r^5=(1/768)/(1/24)=1/32
r^5=1/32
take 5th root of both sides
r=1/2
we have
a5=a1r^4=1/24
evaluate r^4 or (1/2)^4
1/16
a1(1/16)=1/24
times both sides by 16/1
a1=16/24
a1=2/3
the first term is 2/3
Answer:
x≥8
Step-by-step explanation: