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Ksenya-84 [330]
3 years ago
6

Answer 4. Please worth 100 points Answer ASAP!

Mathematics
2 answers:
iragen [17]3 years ago
7 0

Answer:

18/14 or 1 2/7

Step-by-step explanation:

13/14 - 2/14(1/7) = 11/14

11/14 + 7/14(1/2) = 18/14

Olin [163]3 years ago
7 0

\\ \sf\longmapsto \dfrac{13}{14}-\dfrac{1}{7}+\dfrac{1}{2}

\\ \sf\longmapsto \dfrac{13-2+7}{14}

\\ \sf\longmapsto \dfrac{11+7}{14}

\\ \sf\longmapsto \dfrac{18}{14}

\\ \sf\longmapsto \dfrac{9}{7}

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Please help me with number 55 &amp; 56. I need the answer very quick.<br>Use the point-slope formula
AlekseyPX
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4 years ago
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300 students in a high school freshman class are surveyed about what kinds of pets they have. Of the 300 students, 200 have a do
katrin2010 [14]

This Question is not complete

Complete Question:

300 students in a high school freshman class are surveyed about what kinds of pets they have. Of the 300 students, 200 have a dog, 180 have a cat, and 150 have a cat and a dog. Using this information, answer each of the following questions, Let D be the event that a randomly selected student has a dog and C be the event that a randomly selected student has a cat.

a . What is P(D), the probability that a student in the class has a dog?

b. What is P(C), the probability that a student in the class has a cat?

c. What is P(D and C), the probability that a student in the class has a dog and a cat?

d. What is P(D or C), the probability that a student in the class has a dog or a cat?

Answer:

a. 2/3

b) 3/5

c) 1/2

d) 19/ 15 = 1 4/15

Step-by-step explanation:

The formula for probability =

Number of possible outcomes ÷ Number of events.

Total number of Students = 300

Number of Students that have a dog = 200

Number of Students that have a cat = 180

Number of Students that have a dog and cat = 150

a. What is P(D), the probability that a student in the class has a dog?

In the question, the given data is interpreted as :

Number of possible outcomes = 200

Number of events = 300

P(D) = 200/300

= 2/3

Therefore, the probability that a student has a dog = 2/3

b. What is P(C), the probability that a student in the class has a cat?

In the question, the given data is interpreted as :

Number of possible outcomes = 180

Number of events = 300

P(D) = 180/300

= 3/5

Therefore, the probability that a student has a cat = 3/5

c. What is P(D and C), the probability that a student in the class has a dog and a cat?

In the question, the given data is interpreted as :

Number of possible outcomes = 150

Number of events = 300

P(D) = 150/300

= 1/2

Therefore, the probability that a student has a dog and cat = 1/2

d. What is P(D or C), the probability that a student in the class has a dog or a cat?

The is calculated as

P(D) + P(C)

In the above question,

P(D) is calculated as 2/3

P(C) is calculated as 3/5

Therfore, P(D or C), the probability that a student in the class has a dog or a cat is calculated as:

= 2/3 +3/5

= 19/15 = 1 4/15

7 0
3 years ago
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saveliy_v [14]
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You can find out how many she has graded by multiplying 150 by the decimal version of 20% (.20). Then, subtract the number you get by 150.
3 0
3 years ago
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