Answer:
9 years
Step-by-step explanation:
Let the present age = x
Age 6 years ago = x - 6
Thrice my age 6 years ago = 3*(x -6) =3x - 3*6 = 3x - 18
Twice my present age = 2 *x = 2x
Thrice my age 6 years ago be subtracted from
twice my present age = 2x - (3x - 18)
2x - (3x - 18) = x
2x - 3x + 18 = x
-x + 18 = x {Add x to both sides}
18 = x + x
18 = 2x {Divide both sides by 2}
18/2 = x
x = 9 years
<span>In order to determine the value of the numbers, we can set up algebraic equations to solve. For this case, we need to set up two equations since we have two unknown numbers. We do as follows:
let x = first number and y = second number
From the problem statement, we set up equations.
Equation 1 - the numbers have a difference of 0.7
x - y = 0.7
Equation 2 - the numbers have a sum of 1
x + y = 1
Solving for x and y via substitution method,
x - y = 0.7
(1-y) - y = 0.7
1 - 2y = 0.7
-2y = 0.7 - 1 = -0.3
y = 0.15 or 3/20
x - 0.15 = 0.7
x = 0.85 or 17/20
Thus, the two numbers are 0.15 and 0.85.</span>
Answer:
45+13−19+163(3)⋅\−21.5 They also have a pdf if you need it
unit 6-10 answer key.pdf
Step-by-step explanation:
Answer:
550
Step-by-step explanation:
if the numbers after the point starts with a number greater than 5 than you would round the number to the next number (551) but if the number starts with a number lower than 5 then the whole number would be 550. For example: round 122.566 to the nearest whole number. It would be 123. Hope this helps!
Answer:
what is the question?
Step-by-step explanation:
