- I) the probability that the person is female is 8.33%.
- II) the probability that the person has a risk factor heterosexual contact is 6.40%.
- III) the probability that the person is female or has a risk factor of IV drug user is 23.47%.
- IV) the probability that the person is female and has a risk factor of homosexual is 0%.
- V) the probability that the person is male and has a risk factor of IV drug user is 15.13%.
- VI) the probability that the person is female given that the person got the disease from heterosexual contact is 69.38%.
Given the data mentioned in the table, the following calculations must be performed to obtain the requested probabilities:
I.-
(0 + 70 + 136 + 49) / (2,146 + 463 + 60 + 135 + 0 + 70 + 136 + 49) = X
255/3059 = X
0.0833 = X
II.-
196/3059 = X
0.0640 = X
III.-
(255 + 463) / 3059 = X
718/3059 = X
0.2347 = X
IV.-
0/3059 = X
0 = X
V.-
463/3059 = X
0.1513 = X
VI.-
136/196 = X
0.6938 = X
Therefore, I) the probability that the person is female is 8.33%, II) the probability that the person has a risk factor heterosexual contact is 6.40%, III) the probability that the person is female or has a risk factor of IV drug user is 23.47%, IV) the probability that the person is female and has a risk factor of homosexual is 0%, V) the probability that the person is male and has a risk factor of IV drug user is 15.13%, and VI) the probability that the person is female given that the person got the disease from heterosexual contact is 69.38%.
Learn more about maths in brainly.com/question/25815188
|x| = 5
x = 5 or x = -5
You need a graph that has a closed dot on -5 and a closed dot on 5.
Answer: B. Picture B
Answer:
4
Step-by-step explanation:
Answer:
- c(n) = 320·0.96^n
- 28 years
Step-by-step explanation:
Each year, the class size is multiplied by 1 - 4% = 96% = 0.96. After n years, it has been multiplied by that number n times. Repeated multiplication is signified using an exponent.
Class size (c) can be modeled by ...
c(n) = 320·0.96^n
__
You want to find n such that c(n) = 100. Put in that value and solve.
100 = 320·0.96^n
100/320 = 0.96^n . . . . . . . divide by 320
log(100/320) = n·log(0.96) . . . . . . . take logs
log(100/320)/log(0.96) = n ≈ 28.4932
In about 28 years, the class will have 100 students.
