The ten thousands digit is the 8 to the left edge.
You need to increase this digit because the thousands digit is greater than zero.
The answer is 90,000.
If you graph this, your first point will be at (0,5), as the ramp is at the warehouse door but 5 feet up. The second point is (10,0) as it is touching the ground but it's 10 feet away from the warehouse.
To find slope, you do (y2-y1)/(x2-x1).
When substituting in the variables, you get (0-5)/(10-0), which is -5/10, which is simplified to -1/2. Of course, that is when the warehouse is Quadrant II. If you look at it from another point of view, the slope will be positive so your answer is A) 1/2.
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Answer: The company should produce 7 skateboards and 16 rollerskates in order to maximize profit.
Step-by-step explanation: Let the skateboards be represented by s and the rollerskates be represented by r. The available amount of labour is 30 units, and to produce a skateboard requires 2 units of labor while to produce a rollerskate requires 1 unit. This can be expressed as follows;
2s + r = 30 ------(1)
Also there are 40 units of materials available, and to produce a skateboard requires 1 unit while a rollerskate requires 2 units. This too can be expressed as follows;
s + 2r = 40 ------(2)
With the pair of simultaneous equations we can now solve for both variables by using the substitution method as follows;
In equation (1), let r = 30 - 2s
Substitute for r into equation (2)
s + 2(30 - 2s) = 40
s + 60 - 4s = 40
Collect like terms,
s - 4s = 40 - 60
-3s = -20
Divide both sides of the equation by -3
s = 6.67
(Rounded up to the nearest whole number, s = 7)
Substitute for the value of s into equation (1)
2s + r = 30
2(7) + r = 30
14 + r = 30
Subtract 14 from both sides of the equation
r = 16
Therefore in order to maximize profit, the company should produce 7 skateboards and 16 rollerskates.
