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Ganezh [65]
2 years ago
12

Simplify expression -3√2+ 3√8

Mathematics
2 answers:
Ivanshal [37]2 years ago
7 0

Answer:

3√2

~~~~~~~~~~~~~~~

-3√2+ 3√8

-3√2+ 6√2

3√2

Step-by-step explanation:

Arturiano [62]2 years ago
4 0

Answer:

3√2

Step-by-step explanation:

−3√2+3√8

=3√2 (Decimal: 4.242641)

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Solve 3x² + 4x = 2. (2 points)
uysha [10]

Answer:

Step-by-step explanation:

As it is a second order equation, it means that it has two possible answers and they are x_1 and x_2.

The famous quadratic formula for solving any second order equation is the following:

x_{1} = \frac{-b + \sqrt{b^2 - 4 ac}}{2a}\\x_{2}=\frac{-b - \sqrt{b^2 - 4 ac}}{2a}

Where a is the coefficient of x^2, b is the coefficient of x, and c is the free term. In other words,

a = 3\\b=4\\c=-2

as the equation should be in the following form:

a x^2 + bx+c = 0

Therefore the possible answer should be the following,

\frac{-4 + \sqrt{4^2 - 4*3*(-2)}}{2*3}=\frac{-4 +\sqrt{16 + 24}}{6} =\frac{-4 + \sqrt{40}}{6}=\\ \frac{-4 + \sqrt{4*10}}{6} = \frac{-4 + 2\sqrt{10}}{6}\frac{2*(-2 + \sqrt{10})}{2*3} = \frac{-2 + \sqrt{10}}{3}

by dividing the numerator and denominator by 2, we can deduce the following,

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2 years ago
What is m ∠ ZUB?<br> 23.7°<br> 32.8°<br> 33.5<br> 57.2°
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Answer:

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Colton has 8 comedy movies, 6 action movies, 5 fantasy movies, and 1 drama movie on his list of favorite movies.
Alla [95]

Answer:

For every 5 movies on the list there are 2 comedy movies

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Question 3 (1 point)
den301095 [7]

Answer: Pay 250 per month until it’s paid off

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3 years ago
Given that f(a+b)= f(a) + f(b) and f(x) is always positive, what os the value of f(0)?
FrozenT [24]
This is a strange question, and f(x) may not even exist. Why do I say that? Well..

[1] We know that f(a+b) = f(a) + f(b). Therefore, f(0+0) = f(0) + f(0). In other words, f(0) = f(0) + f(0). Subtracting, we see, f(0) - f(0) = f(0) or 0 = f(0).

[2] So, what's the problem? We found the answer, f(0) = 0, right? Maybe, but the second rule says that f(x) is always positive. However, f(0) = 0 is not positive!

Since there is a contradiction, we must either conclude that the single value f(0) does not exist, or that the entire function f(x) does not exist.

To fix this, we could instead say that "f(x) is always nonnegative" and then we would be safe.
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