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3 years ago

Lacie Mae wrote these factor pairs for a number:

Mathematics

1 answer:

nordsb [41]3 years ago

5 0

Lacie Mae wrote the factor pairs for 20 because 1 times 20 equals 20.

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Explain why the slope of line a is 2/6

Firdavs [7]

Answer:

it rises 2 times and run 6

Step-by-step explanation:

4 0

3 years ago

Plz with steps .. it's very hard can anyone plz

liubo4ka [24]

Answer:

Step-by-step explanation:

$\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a} \qquad f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a} \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} }{\dfrac{1}{2\sqrt{x}} }\\\\$

$\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}} =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\$

7 0

3 years ago

Complete the table round answers to the. nearest cent

choli [55]

is there a picture or ss?

4 0

3 years ago

Plz sove and u will earn 30pts

jeyben [28]

Answer:

Pg. 1:

Triangle A: Obtuse

Triangle B: Obtuse

Triangle C: Acute

Triangle D: Right

Pg. 2:

Question 1: Figure A

Question 2: None

Question 3: Figure C

Pg. 3:

Triangle A: Scalene

Triangle B: Equilateral

Triangle C: Isosceles

Triangle D: Isosceles

Pg. 4:

A: Triangle

B: Circle

C: Rectangle

Hope that helped!

Step-by-step explanation:

6 0

3 years ago

What is the value of x?

ddd [48]

Answer:

Step-by-step explanation:

3x+x has to add up to 180

3x+x=180

4x/4=180/4

x=45

6 0

3 years ago

Read 2 more answers