Which expression is equivalent to x^6

The ratio of the surface areas of two similar solids is 4:49. What is the ratio of a volumes?

Fynjy0 [20]

Answer: 8/343

Step-by-Step:

If two similar solids have a scale factor of a:b then,

The ratio of their surface areas (2D) is- a^2:b^2

The ratio of their volume (3D) is- a^3:b^3

First you want to square root the scale factor numbers to find the original value. Then you cube the original numbers to find the answer.

6 0

3 years ago

What is the answer to this?

coldgirl [10]

Answer:

C.) $A=12x-20$

Step-by-step explanation:

The area formula:

$A=l*w$

Insert the values:

$A=4*(3x-5)$

Use the distributive property:

$A=4(3x)+4(-5)\\\\A=12x-20$

:Done

7 0

3 years ago

Limit as x approaches 0 of csc3x/cotx

jolli1 [7]

Hello Meggieh821, to find the lim as x approaches 0 we can check this by inserting a number that is close to 0 that is coming from the left and from the right.

For instance, we can find the lim by using the number -.00001 for x and solve
<span>csc(3x) / cot(x)
</span>csc(3*-.00001) / cot(-.00001) = .333333... = 1 /3

We also need to check coming from the right. We will use the number .00001 for x
csc(3x) / cot(x)
csc(3*.00001) / cot(.00001) = .333333... = 1 /3

So since we are getting 1/3 from the left and right we can say as x approaches 0 the limit is 1/3

<span> $\lim_{x\to 0} \frac{csc(3x)}{cot(x)} = \frac{1}{3}$ </span>

6 0

3 years ago

A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 335335 babies were born

strojnjashka [21]

Answer:

The 99% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

Step-by-step explanation:

Confidence Interval for the proportion:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 335, \pi = \frac{268}{335} = 0.8$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.7437$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.8563$

For the percentage:

Multiplying the proportions by 100.

The 99% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

7 0

3 years ago

Determine if each fraction is a terminating decimal or a repeating decimal. Write each fraction in the correct box.

Alja [10]

-7/9 is repeating
42/50 is terminating
-1/125 is terminating
-77/600 is repeating
179/200 is terminating
5/11 is terminating

The way to figure this out is just by dividing the Numerator (top number) by the denomiter (bottom number)
Example 5÷11=.45454545 repeating

6 0

3 years ago

Which expression is equivalent to x^6 – 5