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steposvetlana [31]
3 years ago
6

The probability that Nick wins in a raffle is given by the expression p . Write down an expression for the probability that Nick

does not win.
Mathematics
1 answer:
svp [43]3 years ago
3 0
There are two possibilities: Nick wins or Nick does not win. Therefore, p, the probability that Nick wins, and the probability that Nick does not win, have to add up to a value of 1. Therefore, the probability that Nick does not win is 1 - p.
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What is the volume in cubic inches of the cylinder, rounded to the nearest cubic inch?
son4ous [18]

\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\ \cline{1-1} r=9\\ h=7 \end{cases}\implies V=\pi (9)^2(7) \\\\\\ V=\pi (81)(7)\implies V=567\pi \implies V\approx 1781.28\implies \stackrel{\textit{rounded up}}{V=1781}

7 0
4 years ago
The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 44,663 miles, with a standard
expeople1 [14]

Answer:

The probability is  P(| \= X- \mu|  < 199 ) = 0.733

Step-by-step explanation:

From the question we are told that

   The mean mileage of a tire is   \mu =  44663

   The standard deviation is  \sigma  =  2594

   The sample size is  n  =  209

 Generally the standard error of mean is mathematically represented as

    \sigma_{x}  =  \frac{\sigma}{\sqrt{n} }

=>  \sigma_{x}  =  \frac{2594}{\sqrt{209} }  

=>  \sigma_{x}  =   179.4      

Generally  the probability that the sample mean would differ from the population mean by less than 199 miles  is mathematically represented as

     P(| \= X- \mu| < 199 ) = P(|\frac{\= X - \mu}{ \sigma_{x}}|  <  \frac{199}{ 179.4})

\frac{\= X -\mu}{\sigma }  =  Z (The  \ standardized \  value\  of  \ \= X )

=>  P(| \= X- \mu|  < 199 ) = P(|Z|  <  \frac{199}{ 179.4})

=>   P(| \= X- \mu|  < 199 ) = P(|Z|<  1.11)

=>   P(| \= X- \mu| < 199 ) = P(-1.11  \le  Z \le 1.11 )

=>   P(| \= X- \mu|  < 199 ) = P(Z  \le 1.11 ) - P( Z \le -1.11 )

From the z  table  the area under the normal curve to the left corresponding to 1.11 and -1.11 is  

        P(Z  \le 1.11 ) = 0.8665

and

       P(Z  \le - 1.11 ) = 0.1335

So

    P(| \= X- \mu| < 199 ) = 0.8665 - 0.1335

=>  P(| \= X- \mu|  < 199 ) = 0.733

8 0
3 years ago
What are the least common multiples of 24 and 36
zaharov [31]
The least common multiple of 24 and 36 is 72
5 0
3 years ago
Which of the following values are solutions to the inequality -8+2x&gt; 5?−8+2x&gt;5?
Oduvanchick [21]

Answer:

-8+2x is less than 5 and - 8+2x is less than 5

8 0
3 years ago
The owner of a restaurant is designing the floor plan for customers. the first floor plan, has 11tables and 20 booths, which sea
Contact [7]
So.
Booths : B
Tables : T

11T + 20B = 182
11T + 22B = 198
( I found he difference in total.)
198 - 182 = 16
(16 divided by the number of difference in Booths)
16 / 2 = 8
( So each Booth seats 8 people- now plug in for B)
11T + 20(8) = 182
11T + 160 = 182
(Move the 160 over to leave T by itself, subtract since it's a positive number)
11T = 182 - 160
11T = 22
(Move the 11 to find T, divide since it's with a Variable)
T = 2
(Plug in your findings for T and B to check if hey are right.)
11(2) + 20(8) = 182
(22) + (160) = 182
182 = 182

And that's how you do it!

I hope it helps!!

5 0
4 years ago
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