Question

The weight of an object above the surface of the Earth varies inversely with the square of the

Answer 1

Answer:

weight =48.71228786pounds

Step-by-step explanation:

$w = \frac{k}{ {d}^{2} } \\ 50 = \frac{k}{ {3960}^{2} } \\ \\ k = 50 \times {3960}^{2} \\ k = 50 \times 15681600 \\ k = 784080000 \\ \\ w = \frac{784080000}{ {d}^{2} } \\ w = \frac{784080000}{16120225} \\ \\ w = 48.71228786 \\ w = 48.7pounds$

Answer 2

Answer:

By using the similarity method:

3960/50 = 4015/W

W = 50 x 4015/3960

W = 50.694

Rounds off to = 50.7