Answer:
-6d^2 + 12d - 3
Step-by-step explanation:
use PEMDAS
parentheses
exponents
multiplication
division
addition
subtraction
use that order to solve problems like that.
Answer:
I can't see the numbers well, but the graph is decreasing from (-inf, minimum) and increasing from (minimum, inf). The minimum is the vertex. Hope this helps!
Step-by-step explanation:
Answer:
A = π(7x + 3)² cm²
Step-by-step explanation:
A = πr² is the appropriate equation. If r = 7x + 3 cm, then the area of this particular circle is:
A = π(7x + 3)² cm²
Answer:
10
Step-by-step explanation:
with reference angle 30°
perpendicular (p) = 5
hypotenuse (h) = x
Now
sin 30° = p / h
1 / 2 = 5 / x
x = 10
Hope it will help :)
Answer:
In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.
But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?
Thank you for all of the help.
That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)
So: the two events are not independent, and so that formula doesn't work.
Fortunately, a formula that does work (always!) is:
P(A∪B)=P(A)+P(B)−P(A∩B)
Hence:
P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330
