Answer:Dos triángulos son congruentes si tienen iguales dos de sus lados respectivos y el ángulo comprendido entre ellos y el ángulo opuesto mayor medida que ellos. 4° Dos triángulos son congruentes si tienen dos lados correspondientes y el ángulo opuesto mayor de estos lados congruentes.
Step-by-step explanation:
First, some housekeeping:
cos = 12/13 is incomplete; "cos" must have an argument (input).
cos x = 12/13 is fine; here "cos" has the argument (input) x.
Given that cos x = 12/13, find sin x. To do this, we'll need to find the length of the opposite side, given that the hypo length is 13 and the adj. side length is 12.
12^2 + opp^2 = 13^2, or opp^2 = 169-144 = 25.
Then the opp side could be either 5 or -5. Let's assume that it's +5, and that angle x is in the first quadrant.
Then sin x = opp / hyp = 5/13 (answer)
cos 2 is an entirely different kind of problem. Here you are told what the argument (input) to the cosine function is (it is 2, which here means 2 radians).
Using a calculator: cos 2 = -0.416. Note that the angle 2 rad is in QII, which is why the "adjacent side" is negative and also why the cos of 2 is negative.
You need to ensure the denominators are the same. To do this you multiply the denominators together.
1/90 + 2/90
However, this is incorrect, as you need to do the same to the numerators, so for the left hand side you multiplied by 9 and for the right hand side you multiplied by 10, so you must do the same for the numerators.
So it should be:
9/90 + 20/90
You can now add this together, to get:
29/90
This is triple checked so I’m not sure why it says reduce the answer fully as that is as far as it can be reduced.
The answer for this is 3(k+6)^2 u need to factor this so use magic X
GMC Answer : 3 because of there
