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vagabundo [1.1K]
3 years ago
12

What things do you need to remember to estimate large numbers

Mathematics
1 answer:
irga5000 [103]3 years ago
3 0

Answer:

remember to round numbers to 1 significant figure

Step-by-step explanation:

usually in an exam when you're asked to estimate the answer to a calculation, usually you round each number to 1 sf and then work on from there.

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xz_007 [3.2K]

If  U\hat{T}J = 100, all angles would be equal, resulting in similar triangles. So B is right

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3 years ago
Can someone please help i really need help i beg you :(
Doss [256]
4x-2
+2
so that leaves 4x
divide by four
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3 years ago
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What is 59.36 Repeated as a fraction
Bas_tet [7]

Answer:

1484/25 is 59.36 as a fraction

3 0
4 years ago
Suppose data made available through a health system tracker showed health expenditures were $10,348 per person in the United Sta
nignag [31]

Answer:

a) 30.08% probability the sample mean will be within $100 of the population mean.

b) 0% probability the sample mean will be greater than $12,600

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the Central Limit Theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 10348, \sigma = 2500, n = 100, s = \frac{2500}{\sqrt{100}} = 250

a. What is the probability the sample mean will be within ±$100 of the population mean?

This is the pvalue of Z when X = 100 divided by s subtracted by the pvalue of Z when X = -100 divided by s. So

Z = \frac{100}{250} = 0.4

Z = -\frac{100}{250} = -0.4

Z = 0.4 has a pvalue of 0.6554, Z = -0.4 has a pvalue of 0.3556

0.6554 - 0.3546 = 0.3008

30.08% probability the sample mean will be within $100 of the population mean.

b. What is the probability the sample mean will be greater than $12,600?

This is 1 subtracted by the pvalue of Z when X = 12600. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{12600 - 10348}{250}

Z = 9

Z = 9 has a pvalue of 1.

1 - 1 = 0

0% probability the sample mean will be greater than $12,600

5 0
3 years ago
How can you use subtraction to complete an addtion pattern
IceJOKER [234]

Answer:Identity Property

Step-by-step explanation:

If you are given a equation like this:

  5+__=35 you can us 35 and subtract 5 to figure out the answer

    30

  <u>-   5</u>

    30

which is 30.This could also be shown as the Identity Property.

7 0
4 years ago
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