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LUCKY_DIMON [66]
3 years ago
8

A company's stock price flucated over a period of four days. The table shows the change in stock price per day. The net change i

n the company's stock price over the four days

Mathematics
1 answer:
DiKsa [7]3 years ago
7 0

Answer:

The net change is -.30

Step-by-step explanation:

increase means add

decrease means subtract

+3.50

-3.70

+3.30

-3.40

-------------

-.30

The net change is -.30

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pickupchik [31]

Answer:

answer is NO ...................

7 0
3 years ago
Prof Liu gave the same quiz to the students in her morning class and in her afternoon class. the average score for the two class
yaroslaw [1]

Answer:

Step-by-step explanation:

Given that Prof  Liu gave the same quiz to the students in her morning class and in her afternoon class. the average score for the two classes combined was 84.

(1) The average score for the students in the morning class was 80

(2) the average score for the students in the afternoon class was 86

Let m be the no of students in I class and n in II class

Total of I class = 80m and

Total of II class = 86n

Total of both classes = 80m +86n

Average =\frac{80m+86n}{m+n} = 84

m cannot be equal to n because in that case average would have been 83

If m >n, then say n =m+a

then average = \frac{80m+86m+86a}{2m+a} =84

Because 86 is more times added, average score would decrease hence we would not get 84.

So I class is getting less score of 80 to get a score average of more than 83 (the average) the class II should have more students.

4 0
4 years ago
One of the smallest pools on the ship has about 45,000 gallons of water in it.
gtnhenbr [62]

Amount of water in the pool at the end of the day is 5457798.7 gallons

<u>Explanation:</u>

Given:

Initial amount of water in the pool = 45,000 gallons

Increase in amount = 0.75 in per minute

Time, t = 1 day

t = 24 X 60 min

t = 1440 min

So,

Increase in amount of water in 1 day = 0.75 in X 1440

                                                             = 1080 in

Volume of 1080 in of water = (1080 in)³

Volume from cubic inch to gallon = 5453298.7 gallon

Amount of water in the pool at the end of the day = 45000 + 5453298.7 gallon

                                                                                   = 5457798.7 gallon                                          

5 0
3 years ago
What the equation of this graph?? I need help
yuradex [85]
X = 3

and

formula -

(y-y1)/(x-x1) = (y2-y1)/(x2-x1)

(x1,y1) = (4,1)
(x2,y2) =( 5,3)

(y-1)/(x-4) = (3-1)/(5-4)

y-1/x-4 = 2/1

y-1 = 2x - 8

y = 2x - 7

the solution will be x= 3 and y = -1
6 0
3 years ago
Julius bought 3 games on sale. the original price of each game was "d" dollars. the expression 3(d - 0.2d) shows the total amoun
xxMikexx [17]
3d-0.6d if you distribute
7 0
4 years ago
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