Donna borrowed $10,500 at a simple interest rate of 4% for 3 years to buy her new car. How much interest would Donna pay and how much is the car altogether ?

<h3>Given:-</h3>

$\bullet$ Principal (P) = $10,500

$\bullet$ Rate of interest (r) = 4%

$\bullet$ Time (t) = 3 years

Interest of Donna and amount of car altogether.

<h2>Solution:-</h2>

We know,

${ \boxed{\rm \red {I \: = \frac{Prt}{100}}}}$

$\therefore$ I = $\frac{10,500 \: × \: 4 \: × \: 3}{100}$

I = $\frac{126,000}{100}$

I = $1260

Now,

Amount of the car = $ (10,500 + 1260)

= $ 11,760

<h3><u>$</u><u>1</u><u>2</u><u>6</u><u>0</u> interest would Donna pay and <u>$</u><u>1</u><u>1</u><u>,</u><u>7</u><u>6</u><u>0</u> is the car altogether. [Answer]</h3>

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