<span>The probability that a house in an urban area will develop a leak is 55%. if 20 houses are randomly selected, what is the probability that none of the houses will develop a leak? round to the nearest thousandth.
Use binomial distribution, since probability of developing a leak, p=0.55 is assumed constant, and
n=20, x=0
and assuming leaks are developed independently between houses,
P(X=x)
=C(n,0)p^x* (1-p)^(n-x)
=C(20,0)0.55^0 * (0.45^20)
=1*1*0.45^20
=1.159*10^(-7)
=0.000
</span>
Answer: 0.75
Step-by-step explanation:
Given : Interval for uniform distribution : [0 minute, 5 minutes]
The probability density function will be :-
The probability that a given class period runs between 50.75 and 51.25 minutes is given by :-
![P(x>1.25)=\int^{5}_{1.25}f(x)\ dx\\\\=(0.2)[x]^{5}_{1.25}\\\\=(0.2)(5-1.25)=0.75](https://tex.z-dn.net/?f=P%28x%3E1.25%29%3D%5Cint%5E%7B5%7D_%7B1.25%7Df%28x%29%5C%20dx%5C%5C%5C%5C%3D%280.2%29%5Bx%5D%5E%7B5%7D_%7B1.25%7D%5C%5C%5C%5C%3D%280.2%29%285-1.25%29%3D0.75)
Hence, the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes = 0.75
Answer:
x=1 4/3
Step-by-step explanation:
2 1/2 pounds of cream cheese for a cheesecake
to find the amount needed to make 2 cheesecakes multiply 2 1/2 times 2
2 1/2 times 2 = 5
you need 5 pounds of cream cheese to make 2 cheesecakes
Answer:
D. 480
Step-by-step explanation:
V= <u>LWH / 3 </u>
<u />
V = <u>12x12x10 / 3</u>
<u>V= 480</u>
