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snow_tiger [21]
3 years ago
7

How many HOURS AND MINUTES are in 135 mins? Explain how you found out the answer as you would to a kid in 2ND GRADE. (Use simple

words)
Mathematics
1 answer:
stiv31 [10]3 years ago
6 0

Answer:

There are 2 hours and 15 minutes in 135 minutes

Step-by-step explanation:

We know that 1 hour = 60 minutes, 2 hours is 120 minutes, 3 hours is 180 minutes and so on. What amount of hours is 135 closest too? 2 hours.

Now that we know the amount of hours there is in 135 minutes, we need to find the rest of the minutes. To find this, we need to use subtraction. Subtracting 120 from 135 gives us 15. So, 135 minutes is equal to 2 hours and 15 minutes.

Hope this helped you (and others) out! If this answer was too complicated for you, please tell me and I will try to make it more easier to understand!

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Estimate the decimal factors, then multiply to estimate the product. 1. 5.3 rounded to the nearest whole number is ____ . 2. 7.9
Licemer1 [7]

Answer:

1. 5

2. 8

3. 40

Step-by-step explanation:

So rounding the factors is an easy way to estimate the product of 5.3 and 7.9.

The real answer is 41.87 and 40 is a reasonable approximation.

40 ≈ 41.87

5 0
4 years ago
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A goalie make 12 saves in 3 games. What is the rate of saves per game?
Elena L [17]

Answer:

Step-by-step explanation:

No of saves in 3 games = 12

Rate of saves per game = 12 ÷ 3 = 4

4 0
3 years ago
X = -60i + 80<br> What is the real part of Z? What is the imaginary part of Z?
Deffense [45]

Answer:

the real part is 80

the imaginary part is -60

Step-by-step explanation:

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4 years ago
Kelsey had 8 entries in her science journal. Last week, she wrote x more entries. How many entries are in her science journal no
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Answer:

Kelsey has 8 plus more entries

8 + x

5 0
2 years ago
A sample survey is designed to estimate the proportion of sports utility vehicles being driven in the state of California. A ran
mart [117]

Answer:

a) The 95% confidence interval would be given (0.070;0.121).

b) "increase the sample size n"

"decrease za/2 by decreasing the confidence"

Step-by-step explanation:

Notation and definitions

X=48 number of vehicles classified as sports utility.

n=500 random sample taken

\hat p=\frac{48}{500}=0.096 estimated proportion of vehicles classified as sports utility vehicles.

p true population proportion of vehicles classified as sports utility vehicles.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

(a) Use a 95% confidence interval to estimate the proportion of sports utility vehicles in California. (Round your answers to three decimal places.)

The confidence interval would be given by this formula :

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.5=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

And replacing into the confidence interval formula we got:

0.096 - 1.96 \sqrt{\frac{0.096(1-0.096)}{500}}=0.070

0.096 + 1.96 \sqrt{\frac{0.096(1-0.096)}{500}}=0.121

And the 95% confidence interval would be given (0.070;0.121).

We are confident (95%) that about 7.0% to 12.1% of vehicles in California are classified as sports utility .  

(b) How can you estimate the proportion of sports utility vehicles in California with a higher degree of accuracy? (HINT: There are two answers. Select all that apply.)

For this case we just have two ways to increase the accuracy one is "increase the sample size n" since if we have a larger sample size the estimation would be more accurate. And the other possibility is "decrease za/2 by decreasing the confidence" because if we decrease the confidence level the interval would be narrower and accurate

7 0
3 years ago
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