The greatest common factor of those numbers is 8.
Answer: 5k +7
Step-by-step explanation: -2k + -7k + 5k is -4K and 2+3=5 -4K +5 and 6k +3k= 9k + 2 then u do -4K plus 9k and get 5k next, 5+2
Explanation:
The angles are <em>vertical angles</em> if the opposites of the rays forming one of the angles are the rays forming the other angle.
More formally, if V is the common vertex, and ...
- R is a point on one of the rays forming Angle 1
- S is a point on the ray that is the opposite of ray VR
- T is a point on the other ray forming Angle 1
- U is a point on the ray that is the opposite of ray VT
Then angle RVT and angle SVU are vertical angles.
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Another way to say this is that points R, V, S are collinear, as are points T, V, U, and the two angles of interest are RVT and SVU.
If the above conditions cannot be met, then the angles are not vertical angles.
The length of the rectangle is 20 inches, and the width of the rectangle is 4 inches if the table runner has an area of 80 square inches. The length and width of the table runner are whole numbers. The length is 5 times greater than the width.
<h3>What is the area of the rectangle?</h3>
It is defined as the space occupied by the rectangle which is planner 2-dimensional geometry.
The formula for finding the area of a rectangle is given by:
Area of rectangle = length × width
The area of the table runner = 80 square inches
Let's assume the length of the rectangle is L and the width is W
Then L = 5×W ...(1)
L×W = 80 ...(2)
Put the value of L in the equation (2)
5W(W) = 80
5W² = 80
W² = 16
W = ±4
Width cannot be negative.
W = 4 inches putting this value in the equation (1)
L = 5(4) = 20 inches
Thus, the length of the rectangle is 20 inches, and the width of the rectangle is 4 inches if the table runner has an area of 80 square inches. The length and width of the table runner are whole numbers. The length is 5 times greater than the width.
Learn more about the area here:
brainly.com/question/14383947
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