Answer:
2.447457627 x 10^6
Step-by-step explanation:
If this helped can i have Brainliest
S= R- 1/3R
The first problem s=18 r-= 6
This is how it works
Use S-= R-1/3R
12= 18-1/3(18)
12= 18-6
12=12
Answer:
Yards: 83.58
Feet: 250.75
Inches: 3009
Step-by-step explanation:
Yards: 1 yard = 36 inches
3009/36= 83.58
So if each yard is 36 inches and there are 83.58 sets of 36 inches in 3009 then that's how many yards you have.
Feet: 1 foot = 12 inches
3009/12= 250.75
Again, if each foot is 12 inches and there are 250.75 sets of 12 inches in 3009 then that's how many feet you have.
Inches: It's already in inches :)
I hope this isn't confusing and I could help!
<span>The <u>correct answers</u> are:
A ray is a bisector of an angle if and only if it splits the angle into two angles; and
A) I can afford to buy a ticket.
Explanation<span>:
For the first question, the first three answers are very specific and true:
A whole number is odd if it is not divisible by 2, and a number is not divisible by 2 if it is odd;
an angle is straight if its measure is 180 degrees, and the measure of an angle is 180 degrees if it is a straight angle;
a whole number is even if it is divisible by 2, and a number is divisible by 2 if it is even.
However, with the fourth choice, we are missing a key word in the definition. A ray is a bisector of an angle if and only if it splits the angle into two <u>CONGRUENT</u> angles. It is not just a ray that cuts an angle into two pieces, the pieces must be equal.
For the second question, the Law of Detachment says if our conditional "if p, then q" is true and p is true, then q must also be true.
For this question, "I can go to the concert if I can afford to buy a ticket" is true as well as "I can go to the concert." This means "I can afford to buy a ticket" must be true as well.</span></span>
In order to answer the question, it's absolutely essential to have
enough of a description of the object to know which of its parts
'X', 'Y', and 'Z' are, and what other parts it may have.
An ideal way to accomplish this would have been for you to include the
picture that accompanies the question, wherever you copied it from.
