This is how to solve this
Answer:
D. 22,417 feet
Step-by-step explanation:
Fine the diagram in the attachment for proper elucidation. Using the SOH, CAH, TOA trigonometry identity to solve for the distance (x) from the plane (P) to the observer (O), the longest side x is the hypotenuse and the side facing the angle of elevation is the opposite.
Hypotenuse = x and Opposite = 15,000feet
According to SOH;


Hence the distance (x) from the plane P to the observer O is approximately 22,417 feet
Let's start with what we know:
Smaller canvas:
Length (

) = 3ft
Width (

) = 5ft
Larger canvas:
Length (

) = ?
Width (

) = 10ft
Since these are similar rectangles, we can cross-multiply to calculate the missing length. Here's that formula:

So let's plug it all in from above:

Now we cross multiply by multiplying the top-left by the bottom-right and vice versa:


Now divide each side by 5 to isolate


The 5s on the right cancel out, leaving us with:

So the length of the larger canvas is
6 ft
Answer:
B
Step-by-step explanation:
The interquartile range is the difference between the upper quartile and the lower quartile.
The upper quartile is the right side value of the box
The lower quartile is the left side value of the box
upper quartile = 61 and lower quartile = 39
IQR = 61 - 39 = 22 → B