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Tanzania [10]
3 years ago
11

What is the answer to 5(n-7)=2(n+14) work

Mathematics
2 answers:
aivan3 [116]3 years ago
7 0

Answer:

The answer is n=21.

Step-by-step explanation:

To solve the equation for (n), start by using the distributive property on both sides of the equation. The distributive property is multiplying the sum of two or more addends by a number which will give the same result as multiplying each addend individually by the number and then adding the products together.

The equation will look like 5n-35=2n+28 after using the distributive property. Next, add 35 to both sides of the equation, which will look like 5n=2n+63, and then subtract (2n) from both sides of the equation, which will look like 3n=63. The next step is to simplify the equation, which will look like n=21, and the final answer to the equation will be n=21.

pickupchik [31]3 years ago
5 0

Answer:

n = 21

Step-by-step explanation:

5(n-7)=2(n+14)

Distribute

5n -35 = 2n+28

Subtract 2n from each side

5n-2n -35 = 2n-2n +28

3n-35 =28

Add 35 to each side

3n-35+35 = 28+35

3n = 63

Divide by 3

3n/3 = 63/3

n =21

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3 years ago
Points A and B lie on line EF.
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3 years ago
If you were to roll a standard six sided die, what is the probability of rolling a number less than what three other people roll
Elena-2011 [213]

Answer:

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Step-by-step explanation:

7 0
3 years ago
3. Make a class frequency table using 2 rule of the following data. Find the Mean and make a Cumulative frequency Histogram [10]
sashaice [31]

Answer:  Mean = 284

Step-by-step explanation:

<u>Data:</u>

125, 126, 127, 127, 137

201, 202, 207, 211, 215, 218, 224, 237, 261

301, 308, 310, 315, 330, 330, 360, 380, 393, 394

401, 401, 410, 421, 422, 424

<u>Class Frequency Table:</u>

\boxed{\begin{array}{c|c|c}\underline{\text{Intervals}}&\underline{\text{\qquad Frequency\qquad}}&\underline{\text{Cumulative Frequency}}\\0-49&0&0\\50-99&0&0\\100-149&5&5\\150-199&0&5\\200-249&8&13\\250-299&1&14\\300-349&6&20\\350-399&4&24\\400-449&6&30\\450-499&0&30\end{array}}\\.\qquad \qquad \qquad \qquad \quad \ 30                                                                    

<u>Mean:</u>

The sum of the numbers divided by the quantity of numbers:

8518/30 = 283.933

<u>Cumulative Frequency Histogram:</u>

Create the graph based on the Interval and Cumulative Frequency of the class frequency table above. <em>(see image)</em>

<em />

<em />

3 0
4 years ago
What is the value expression 10p-5/5+3(p-1) when p = 2
nasty-shy [4]

For this case we have the following expression:

\frac {10p-5} {5 + 3 (p-1)}

We must find the value of the expression when cp = 2.

Substituting the value of "p" we have:

\frac {10 (2) -5} {5 + 3 ((2) -1)} =\\\frac {20-5} {5 + 3 (1)} =\\\frac {20-5} {5 + 3} =\\\frac {15} {8}

Thus, the value of the expression when p = 2, is\ \frac {15} {8}

ANswer:

\frac {15} {8}

7 0
3 years ago
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