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leva [86]
3 years ago
15

Please simplify this fraction

Mathematics
1 answer:
saw5 [17]3 years ago
6 0
I hope this helps you

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Solve:<br><br> Picture attached
STatiana [176]

Answer:

24

Step-by-step explanation:

3 0
3 years ago
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Find the direction cosines and direction angles of the vector. (Give the direction angles correct to the nearest degree.) 5, 1,
Dahasolnce [82]

Answer:

The direction cosines are:

\frac{5}{\sqrt{42} }, \frac{1}{\sqrt{42} }  and  \frac{4}{\sqrt{42} }  with respect to the x, y and z axes respectively.

The direction angles are:

40°,  81° and  52° with respect to the x, y and z axes respectively.

Step-by-step explanation:

For a given vector a = ai + aj + ak, its direction cosines are the cosines of the angles which it makes with the x, y and z axes.

If a makes angles α, β, and γ (which are the direction angles) with the x, y and z axes respectively, then its direction cosines are: cos α, cos β and cos γ in the x, y and z axes respectively.

Where;

cos α = \frac{a . i}{|a| . |i|}               ---------------------(i)

cos β = \frac{a.j}{|a||j|}               ---------------------(ii)

cos γ = \frac{a.k}{|a|.|k|}             ----------------------(iii)

<em>And from these we can get the direction angles as follows;</em>

α =  cos⁻¹ ( \frac{a . i}{|a| . |i|} )

β = cos⁻¹ ( \frac{a.j}{|a||j|} )

γ = cos⁻¹ ( \frac{a.k}{|a|.|k|} )

Now to the question:

Let the given vector be

a = 5i + j + 4k

a . i =  (5i + j + 4k) . (i)

a . i = 5         [a.i <em>is just the x component of the vector</em>]

a . j = 1            [<em>the y component of the vector</em>]

a . k = 4          [<em>the z component of the vector</em>]

<em>Also</em>

|a|. |i| = |a|. |j| = |a|. |k| = |a|           [since |i| = |j| = |k| = 1]

|a| = \sqrt{5^2 + 1^2 + 4^2}

|a| = \sqrt{25 + 1 + 16}

|a| = \sqrt{42}

Now substitute these values into equations (i) - (iii) to get the direction cosines. i.e

cos α = \frac{5}{\sqrt{42} }

cos β =  \frac{1}{\sqrt{42} }              

cos γ =  \frac{4}{\sqrt{42} }

From the value, now find the direction angles as follows;

α =  cos⁻¹ ( \frac{a . i}{|a| . |i|} )

α =  cos⁻¹ ( \frac{5}{\sqrt{42} } )

α =  cos⁻¹ (\frac{5}{6.481} )

α =  cos⁻¹ (0.7715)

α = 39.51

α = 40°

β = cos⁻¹ ( \frac{a.j}{|a||j|} )

β = cos⁻¹ ( \frac{1}{\sqrt{42} } )

β = cos⁻¹ ( \frac{1}{6.481 } )

β = cos⁻¹ ( 0.1543 )

β = 81.12

β = 81°

γ = cos⁻¹ ( \frac{a.k}{|a|.|k|} )

γ = cos⁻¹ (\frac{4}{\sqrt{42} })

γ = cos⁻¹ (\frac{4}{6.481})

γ = cos⁻¹ (0.6172)

γ = 51.89

γ = 52°

<u>Conclusion:</u>

The direction cosines are:

\frac{5}{\sqrt{42} }, \frac{1}{\sqrt{42} }  and  \frac{4}{\sqrt{42} }  with respect to the x, y and z axes respectively.

The direction angles are:

40°,  81° and  52° with respect to the x, y and z axes respectively.

3 0
3 years ago
Solve 2x2 − 12x + 20 = 0. (5 points) 3 ± i 3 ± 2i 1 ± 2i 2 ± 3i
Oksi-84 [34.3K]
The answer is 3+-i



I hope this helps!!!!!!!!
4 0
3 years ago
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X + x + x = 54<br> What’s the answer for this
Oliga [24]

Answer:

x = 18

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

x+x+x=54

(x+x+x)=54(Combine Like Terms)

3x=54

3x=54

Step 2: Divide both sides by 3.

3x  3 = 54

3 x=18

Answer:

x=18

8 0
2 years ago
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Can someone explain how to do this and add the formula please
lisabon 2012 [21]

Answer:

5 is 35 and 6 is 50

Step-by-step explanation:

To solve 5, you need to know how many degrees is the line, which is 180 because lines are 180 degrees. You then subtract 110 from 180 which equals to 70. What you have left now is 2k. A number times 2 will equal to 70, so k=35.

For 6, if you ever see two lines intersecting each other, it means that it is 360 degrees. We already have one angle, which is 120. The other angle is d+70 degrees, and any angle that is reflecting the other angle will have the same value. So, d equals 50

(sorry if you still can't understand it I'm not good at English

6 0
2 years ago
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