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Sophie [7]
3 years ago
14

If M={a,b,c,d} and N={c,b,e,f},find the value of M-N​

Mathematics
2 answers:
kumpel [21]3 years ago
8 0

Answer:

M-N= {a,d}

Step-by-step explanation:

subtract the common elements

MrRa [10]3 years ago
8 0

(a, d)

(

Step-by-step explanation:

because a and d are not in N ,

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Salsk061 [2.6K]

Answer:

I think (-3,-1)

Step-by-step explanation:

may this answer help you

4 0
3 years ago
Read 2 more answers
I NEED HELP!!! ASAP!!
Vesnalui [34]

Answer:

1)

Perimeter=24 inches

Area= around 43.46 inches

Step-by-step explanation:

1) Perimeter = 3in * number of sides

Perimeter = 3*8 = 24

Area= 2(1+ square root of 2) length of one side squared

=42.46

2)

Perimeter = 24

Area= 43.46 inches squared- 3inches

3)

Perimeter = 24

Area= 43.46- triangle area

triangle area = height x base /2

Height = 3, we can compare it.

Base = 3

Triangle = 9/2

Area = 43.46- 4.5

Area =38.96

Can't see 4 and 5 for some reason

6)

Perimeter =  30

Area = 61.94

Sorry if its incorrect, I am just 4th grade :(

8 0
3 years ago
Select the correct answer.
valina [46]
The answer for this one is C
6 0
3 years ago
|x-3|+4=12 show all steps <br>Please
SOVA2 [1]

Answer:

|x-3|+4 = 12

|x-3| = 12-4

|x-3| = 8

now solve for both positive and negative values

x - 3 = 8      |   x - 3 = -8

x = 8 + 3     |   x = - 8 + 3

x = 11          |    x = -5

solution set : { 11, -5 }

Step-by-step explanation:


3 0
4 years ago
1. Trapezoid KLMN has vertices K(1, 3) , L(3, 1) , M(3, 0) , and N(1, −2) .
chubhunter [2.5K]

Answer:


Step-by-step explanation:

(A) The vertices of the trapezoid KLMN are K(1, 3) , L(3, 1) , M(3, 0) , and N(1, −2)

Now, KL= \sqrt{(3-1)^{2}+(1-3)^{2}}=\sqrt{8}[/tex]

LM=\sqrt{(3-3)^{2}+(0-1)^{2}}=1

MN=\sqrt{(1-3)^{2}+(-2-0)^{2}}=\sqrt{8}

NK=\sqrt{(1-1)^{2}+(-2-3)^{2}}=5

Now, as KL and MN  are equal, therefore, KLMN is an isosceles trapezoid.

(B) Since  m∠XWY=47°, therefore ∠XWZ=47+47=94° and ∠ZYW=18°, therefore ∠XYZ=36°( as diagonals bisect the angles)

In ΔXWO,

∠XWO+∠WXO+∠WOX=180°(Angle sum property)

∠WXO=43°

Also, from ΔXOY,

∠OXY=72° using the angle sum property.

Therefore, ∠WXY=43+72=115°

Now, sum of all the angles of a quadrilateral is equal to 360°, therefore

∠WXY+∠XYZ+∠YZW+∠ZWX=360°

115°+36°+∠YZW+94°=360°

∠YZW=115°

Therefore,∠WZY=115°

(C) Since, AB and CD are the two parallel lines as the slope of both the sides are equal.

LetM be the mid point of AB, therefore M=(\frac{-2+4}{2}, \frac{4+3}{2})

=(1,\frac{7}{2})

Also, let N be the mid point of DC, therefore,

N=(\frac{4-2}{2},\frac{-2-5}{2})

=(1,\frac{-7}{2})

Now, length of the mid segment MN= \sqrt{(1-1)^{2}+(\frac{7}{2}+\frac{7}{2})^{2}}=\sqrt{0+49}=7 cm

(D)Given: Kite PQRS,  TS=6cm and TP=8cm

Then, From triangle TSP, we have

(SP)^{2}=(TS)^{2}+(TP)^{2}

(SP)^{2}=36+64

SP=10cm

8 0
3 years ago
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