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Sophie [7]
3 years ago
14

If M={a,b,c,d} and N={c,b,e,f},find the value of M-N​

Mathematics
2 answers:
kumpel [21]3 years ago
8 0

Answer:

M-N= {a,d}

Step-by-step explanation:

subtract the common elements

MrRa [10]3 years ago
8 0

(a, d)

(

Step-by-step explanation:

because a and d are not in N ,

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Which statement about the quadratic parent function is true?
nikitadnepr [17]
The correct answer is B) its graph is symmetrical about the y-axis.

A quadratic graph cannot be "folded" across the x-axis.
The domain, or set of inputs, is all real numbers; there is no value of x for which there will be no y.
The range, or set of outputs, is not all real numbers; there are values of y that will not be used in the graph.
3 0
3 years ago
PLEASE HELP ME!!!! I NEED THIS QUICKLY!!
zloy xaker [14]

Part A: y=-\frac{5}{4} x+\frac{35}{2} is the equation of the line.

Part B: Anika worked 17.5 hours on day 0.

Part C: The setup time decreases with 1 hour and 15 min per day.

Explanation:

Part A: Let us find the equation of the line using the points (2,15) and (6,10)

The equation of the line is given by,

y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \cdot\left(x-x_{1}\right)

Substituting, we get,

y-15=\frac{10-15}{6-2} (x-2)

Simplifying, we have,

y-15=-\frac{5}{4} (x-2)

y-15=-\frac{5}{4} x+\frac{5}{2}

Subtracting both sides by 15, we get,

y=-\frac{5}{4} x+\frac{35}{2}

Hence, the equation of the line is y=-\frac{5}{4} x+\frac{35}{2}

Part B: To determine the number of hours Anika worked on day 0, let us substitute x = 0 in the equation of the line.

Thus, we get,

y=\frac{35}{2}\\y=17.5

Hence, Anika worked 17.5 hours on day 0.

Part C: The setup time decrease per day can be determined using the slope.

The formula for slope is given by

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Substituting , we have,

m=\frac{10-15}{6-2}=-\frac{5}{4}

Converting the fraction into hours and minutes, we get,

-\frac{5}{4}\times60=-75 min

Since, 1 hour = 60 min

Subtracting 60 and 75 = 15 min

Thus, the setup time decreases with 1 hour and 15 min per day.

6 0
3 years ago
Clark and Lana take a 30-year home mortgage of $128,000 at 7.8%, compounded monthly. They make their regular monthly payments fo
svp [43]

Answer:

Step-by-step explanation:

From the given information:

The present value of the house = 128000

interest rate compounded monthly r = 7.8% = 0.078

number of months in a year n= 12

duration of time t = 30 years

To find their regular monthly payment, we have:

PV = P \begin {bmatrix}  \dfrac{1 - (1 + \dfrac{r}{n})^{-nt}}{\dfrac{r}{n}}    \end {bmatrix}

128000 = P \begin {bmatrix}  \dfrac{1 - (1 + \dfrac{0.078}{12})^{- 12*30}}{\dfrac{0.078}{12}}    \end {bmatrix}

128000 = 138.914 P

P = 128000/138.914

P = $921.433

∴ Their regular monthly payment P = $921.433

To find the unpaid balance when they begin paying the $1400.

when they begin the payment ,

t = 30 year - 5years

t= 25 years

PV= 921.433 \begin {bmatrix}  \dfrac{1 - (1 - \dfrac{0.078}{12})^{25*30}}{\dfrac{0.078}{12}}    \end {bmatrix}

PV = $121718.2714

C) In order to estimate how many payments of $1400  it will take to pay off the loan, we have:

121718.2714 =  \begin {bmatrix}  \dfrac{1300  (1 - \dfrac{12.078}{12}))^{-nt}}{\dfrac{0.078}{12}}    \end {bmatrix}

121718.2714 = 200000  \begin {bmatrix}  (1 - \dfrac{12.078}{12}))^{-nt}   \end {bmatrix}

\dfrac{121718.2714}{200000 } =  \begin {bmatrix}  (1 - \dfrac{12.078}{12}))^{-nt}   \end {bmatrix}

0.60859 =  \begin {bmatrix}  (1 - \dfrac{12}{12.078}))^{nt}   \end {bmatrix}

0.60859 = (0.006458)^{nt}

nt = \dfrac{0.60859}{0.006458}

nt = 94.238 payments is required to pay off the loan.

How much interest will they save by paying the loan using the number of payments from part (c)?

The total amount of interest payed on $921.433 = 921.433 × 30(12) years

= 331715.88

The total amount paid using 921.433 and 1300 = (921.433 × 60 )+( 1300 + 94.238)

= 177795.38

The amount of interest saved = 331715.88  - 177795.38

The amount of interest saved = $153920.5

6 0
3 years ago
Pls help me i will give brainliest
qwelly [4]

Answer:

both the groups have the same value for the first quartile

7 0
3 years ago
8. Solve X=Students &amp; Y=Teachers<br> X+Y=24<br> X=3Y
Len [333]

Answer:

x=18, y= 6

Step-by-step explanation:

if x+y=24

x= 24- y

in second case

x= 3y

24_ y = 3y

24=4y

y= 6

hence x = 24 _6 = 18

5 0
3 years ago
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