The closest it gets is 6*9 which is 54
The probability of winning exactly 21 times is:-0.32
Given,
The probability of winning on an arcade game, p = 0.659
Number of times you play arcade game, n = 30
By assuming this as a normal distribution, we get
Mean=μ=30×0.659 =19.77
Standard deviation, σ = 
= 
≈ 2.60
Let X be a binomial variable
Then, the z score for x = 21 will be:
z = (x - μ) / σ = 
≈ 0.47
Now, the probability of winning exactly 21 times
P (x ≥ z) = P (21 ≥ 0.47) = 0.32
Hence the probability of winning exactly 21 times is 0.32
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17.3% is the percentage of shots he was successful with.<span />
Answer:
x=2
Step-by-step explanation:
5(7-x)-3(x+4)-4=4(x-3)+7
35-5x-3x-12-4=4x-12+7
19-8x=4x-5
+8x. +8x
24=12x
x=2
8 quarts = 32 cups
So we have a ratio of 32 : 3/4 cups
And the equal ratio of 4: x
So to solve for x, divide 3/4 by 8.
3/4 divided by 8 = 3/4 •1/8 = 3/32 of a cup of green paint.