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2 years ago

Help me in this problem please !!

Mathematics

1 answer:

frozen [14]2 years ago

5 0

Answer:

SECTION B

Step-by-step explanation:

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Qhat is 3 groupps of 1/8

iragen [17]

Answer: 3/8ths

Step-by-step explanation: 1/8+1/8+1/8=3/8

4 0

2 years ago

Is (1, 3) a solution to the system of equations listed below? (1 point) y= 6x -3 y = x - 2

ololo11 [35]

Answer:

The solution for given system of equation is: $x=\frac{1}{5}\:and\:y=\frac{-9}{5}$ and ordered pair is: $\mathbf{(\frac{1}{5},\frac{-9}{5})}$

So, (1,3) is not solution to the given system of equations.

Step-by-step explanation:

we can solve the system of equations to find the value of x and y and then verify if (1,3) is a solution or not.

The system of equation given is:

$y=6x-3\\y=x-2$

Solving:

Let:

$y=6x-3--eq(1)\\y=x-2--eq(2)$

Put value of y from equation 2 into equation 1

$y=6x-3\\Put\:y=x-2\\x-2=6x-3\\x-6x=-3+2\\-5x=-1\\x=\frac{-1}{-5}\\x=\frac{1}{5}$

Now, put value of x in equation 2 to find value of y

$y=x-2\\Put\:x=\frac{1}{5} \\y=\frac{1}{5} -2\\y=\frac{1-2*5}{5} \\y=\frac{1-10}{5}\\ y=\frac{-9}{5}$

So, the solution for given system of equation is: $x=\frac{1}{5}\:and\:y=\frac{-9}{5}$ and ordered pair is: $\mathbf{(\frac{1}{5},\frac{-9}{5})}$

So, (1,3) is not solution to the given system of equations.

7 0

2 years ago

The question is in the picture.

harkovskaia [24]

Answer:

1. 3sqrt(2)

Choice C

2. 2sqrt(3)

Choice D

Step-by-step explanation:

1. sqrt(x+3)

sqrt(15+3)

sqrt(18)

sqrt(9*2)

sqrt(9)sqrt(2)

3sqrt(2)

Choice C

2. 6/sqrt(x)

6/sqrt(3)

no radicals in the denominator, multiply by 1 in the form of the radical

6/sqrt(3) * sqrt(3)/sqrt(3)

6sqrt(3)/ (sqrt(3)*sqrt(3))

6sqrt(3)/3

2sqrt(3)

Choice D

8 0

2 years ago

Write down the first five terms of the sequence start at 26 and subtract 3 B start at -3 and add 10

MissTica

Step-by-step explanation:

Sequence 1:

term1=26

term2=26-3=23

term3=23-3=20

term4=20-3=17

term5=17-3=14

sequence2:

term1=-3

term2=-3+10=7

term3=7+10=17

term4=17+10=27

term5=27+10=37

8 0

3 years ago

I will give you brainliest if you actually help me explain this in words :,(

just olya [345]

By representing radicals as numbers with rational exponents, the properties of rational exponents can be used to simplify statements containing radicals or rational exponents. This allows you to apply the same rational exponent qualities to them.

<h2>☆彡Hanna</h2>

#CarryOnLearning

3 0

2 years ago

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