What are the x- and y-intercepts of g(x) = 4 - X2?
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Answer:
see explanation
Step-by-step explanation:
Where the graph crosses the x- axis the y- coordinate is zero.
Let y = 0 in the equation and solve for x
- 4(0) = 15 - 5x, that is
15 - 5x = 0 ( subtract 15 from both sides )
- 5x = - 15 ( divide both sides by - 5 )
x = 3 ← x- intercept ⇒ (3, 0 )
Where the graph crosses the y- axis the x- coordinate is zero.
Let x = 0 in the equation and solve for y
- 4y = 15 - 5(0), that is
- 4y = 15 ( divide both sides by - 4 )
y = - ← y- intercept ⇒ (0, -
)