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2 years ago

Roberto wrote the pattern shown below. What is the rule for following Roberto's pattern?

Mathematics

1 answer:

Molodets [167]2 years ago

4 0

Answer:

its b because

Step-by-step explanation:

24÷12 is 2 and if u do 12 × 2 and keep going u will get the next answer

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On Thursday, 72% of the customers at a frozen yogurt shop ordered vanilla frozen yogurt. If 180 customers ordered vanilla frozen

Ber [7]

180 of 72% is 129.6. 180*72= 12960. Since 72% = .72, you need to put the decimal 2 places behind the decimal.

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3 years ago

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frozen [14]

1.5m^2 I believe. I could be wrong but I hope I have helped!

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2 years ago

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What expressions is equivalent to −2(x−5)?

Ksenya-84 [330]

Answer:

-2x + 10

Step-by-step explanation:

Distribute -2 to x - 5 to simplify the expression. So we get: -2(x - 5) = -2x + 10.

6 0

2 years ago

The graph of Y = COS X+ż is the graph of the y = cos(x) shifted in which direction?

rjkz [21]

Answer:

2 units up

Step-by-step explanation:

You're just taking the entire graph of cos(x) and then adding 2 so it moves everything up. If you added 2 to x BEFORE taking the cosine

(like y = cos (x+2) ), then you would shift it left 2. Adding and subtracting from the x moves everything left or right. Adding or subtracting at the end just moves it up and down.

3 0

3 years ago

1. The number of rabbits on an island is increasing exponentially.

Zina [86]

Answer:

<em>There are approximately 114 rabbits in the year 10</em>

Step-by-step explanation:

<u>Exponential Growth </u>

The natural growth of some magnitudes can be modeled by the equation:

$P=P_o(1+r)^t$

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.

We are given two measurements of the population of rabbits on an island.

In year 1, there are 50 rabbits. This is the point (1,50)

In year 5, there are 72 rabbits. This is the point (5,72)

Substituting in the general model, we have:

$50=P_o(1+r)^1$

$50=P_o(1+r)\qquad\qquad[1]$

$72=P_o(1+r)^5\qquad\qquad[2]$

Dividing [2] by [1]:

$\displaystyle \frac{72}{50}=(1+r)^{5-1}=(1+r)^{4}$

Solving for r:

$\displaystyle r=\sqrt[4]{\frac{72}{50}}-1$

Calculating:

r=0.095445

From [1], solve for Po:

$\displaystyle P_o=\frac{72}{(1+r)^5}$

$\displaystyle P_o=\frac{72}{(1.095445)^5}$

$P_o=45.64355$

The model can be written now as:

$P=45.64355(1.095445)^t$

In year t=10, the population of rabbits is:

$P=45.64355(1.095445)^{10}$

P = 113.6

$P\approx 114$

There are approximately 114 rabbits in the year 10

5 0

2 years ago