F(x) = |x| is an even function.
Answer:
![f^{-1}=+-\sqrt{x+1}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%3D%2B-%5Csqrt%7Bx%2B1%7D)
Step-by-step explanation:
f(x) = x^2 -1
We need to find f^-1(x)
WE find inverse of f(x)
Replace f(x) with y
![y= x^2 -1](https://tex.z-dn.net/?f=y%3D%20x%5E2%20-1)
Replace x with y and y with x
![x= y^2 -1](https://tex.z-dn.net/?f=x%3D%20y%5E2%20-1)
Solve for y
add 1 on both sides , ![x+1= y^2](https://tex.z-dn.net/?f=x%2B1%3D%20y%5E2)
To remove square , take square root on both sides
![\sqrt{x+1} =\sqrt{y^2}](https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B1%7D%20%3D%5Csqrt%7By%5E2%7D)
![\sqrt{x+1} =y](https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B1%7D%20%3Dy)
![y=+-\sqrt{x+1}](https://tex.z-dn.net/?f=y%3D%2B-%5Csqrt%7Bx%2B1%7D)
Replace y with f^-1
![f^{-1}=+-\sqrt{x+1}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%3D%2B-%5Csqrt%7Bx%2B1%7D)
I think 15 are orange and 10 are green