I will give brainliest !!

Mathematics

1 answer:

tekilochka [14]3 years ago

6 0

Answer:

Step-by-step explanation:

When all the members in a domain has only but one member in the do main then function has been satisfied.

considering a situation of,

4 1

6 1

8 2

the domain has only one member in the Co domain hence which makes it a function

You might be interested in

What is the quotient: (6x4 + 15x3 + 10x2 + 10x + 4) ÷ (3x2 + 2)?

Kryger [21]

Answer: Option 'C' is correct.

Step-by-step explanation:

Since we have given that

$\frac{\left(6x^4+15x^3+10x^2+10x+4\right)}{\left(3x^2+2\right)}$

Now, we will find the quotient by factoring the numerator:

$\mathrm{Use\:the\:rational\:root\:theorem}\\a_0=4,\:\quad a_n=6\\\\\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:4,\:\quad \\\mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2,\:3,\:6\\\\\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:4}{1,\:2,\:3,\:6}\\\\-\frac{2}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+2\\\\=\left(x+2\right)\frac{6x^4+15x^3+10x^2+10x+4}{x+2}\\\\=\frac{6x^4+15x^3+10x^2+10x+4}{x+2}=6x^3+3x^2+4x+2\\\\$

Now, we will factor it again:

$=\left(6x^3+3x^2\right)+\left(4x+2\right)\\\\=2\left(2x+1\right)+3x^2\left(2x+1\right)\\\\=\left(2x+1\right)\left(3x^2+2\right)$

At last we get our factorised form :

$=\left(x+2\right)\left(2x+1\right)\left(3x^2+2\right)\\\\=\frac{\left(x+2\right)\left(2x+1\right)\left(3x^2+2\right)}{3x^2+2}\\\\=\left(x+2\right)\left(2x+1\right)\\\\=2x^2+5x+2$