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3 years ago

Where would you put the decimal in this product? 3.21 x 4.8 = 1 5 4 0 8

Mathematics

2 answers:

3241004551 [841]3 years ago

7 0

Answer:

15.408

Step-by-step explanation:

hope this helps :3

if it did pls mark brainliest

Dmitry [639]3 years ago

5 0

You would place it like this: 15.408

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What is the slope between each pair of points. (-5,-2) and (9,2)

zzz [600]

Answer: 2/7

Step-by-step explanation:

You subtract the y intercepts and put it over the x intercepts

2-(-2)=4 and 9-(-5)=14 so it is 4/14 which sinplifies to 2/7

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3 years ago

Find the value(s) of k such that 4x² + kx + 4 = 0 has 1 rational solution

Blababa [14]

Answer:

If you mean only one rational solution, the answer is

$k_1 = 8, k_2 = -8$

If you mean at least 1 rational solution, the answer is

$k\in (-\infty, -8]\cup[8, \infty)$

Step-by-step explanation:

$4x^2 + kx + 4 = 0$

Let's calculate the discriminant.

$\Delta = b^2 - 4ac$

$\Delta = k^2 -4 \cdot 4 \cdot 4$

$\Delta = k^2 -64$

Now, remember that:

$\text{If } \Delta > 0 : \text{2 Real solutions}$

$\text{If } \Delta = 0 : \text{1 Real solution}$

$\text{If } \Delta < 0 : \text{No Real solution}$

Therefore, I will just consider the first two cases.

$k^2 - 64 > 0$

and

$k^2 -64 = 0$

$\boxed{\text{For } k^2 - 64 > 0}$

$k^2 > 64 \Longleftrightarrow k>\pm\sqrt{64} \Longleftrightarrow k\in (-\infty, -8)\cup(8, \infty)$

$\boxed{\text{For } k^2 - 64 = 0}$

$k^2 = 64 \Longleftrightarrow k=\pm\sqrt{64} \implies k_1 = 8, k_2 = -8$

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3 years ago

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Step-by-step explanation:

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5(7-2) +3

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