All categories

2 years ago

I need help solving this systems of equations problemn

Mathematics

1 answer:

Doss [256]2 years ago

6 0

Answer:

thequantity in column b is greater

Step-by-step explanation:

7a+b=33......(1)

3a-b=7.........(2)

(1)+(2)

7a+b+3a-b=33+7

10a+b-b=40

10a=40

a=4

in equation (1)

7*4+b=33

28+b=33

b=33-28

b=5

b>a

You might be interested in

A rich farmer's Will states that 1/4 of his property should be given to his son, 2/3 of the remainder to his internal family 5/6

postnew [5]

Answer:

Step-by-step explanation: 1/2

5 0

3 years ago

The equation of a line is y = 1.5x − 2. What are its slope and y-intercept?

andre [41]

This equation is written in slope intercept form, y=mx+b, with m being the slope and b being the y-intercept.

The slope of the line is 1.5 and the y-intercept is -2. The answer is A.

I hope this helps ;)

4 0

2 years ago

Read 2 more answers

If x is 5, then 6x= 1. 30x 2. 5x 3. 30

Fittoniya [83]

Answer:

Step-by-step explanation:

6*5=30

3 0

2 years ago

Read 2 more answers

I need help with everything.

LekaFEV [45]

Step-by-step explanation:

5. 102 = 6( 1 + 4p)

102 = 6 + 24p

102 - 6 = 24p

96 = 24p

96/ 24 = p

4 = p

5 0

2 years ago

83 random samples were selected from a normally distributed population and were found to have a mean of 32.1 and a standard devi

arlik [135]

Answer:

$\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}$

$4.525 \leq \sigma^2 \leq 7.602$

Now we just take square root on both sides of the interval and we got:

$2.127 \leq \sigma \leq 2.757$

Step-by-step explanation:

Information given

$\bar X=32.1$ represent the sample mean

$\mu$ population mean (variable of interest)

s=2.4 represent the sample standard deviation

n=83 represent the sample size

Confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The degrees of freedom given by:

$df=n-1=8-1=7$

The confidence level is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical values.

The excel commands would be: "=CHISQ.INV(0.05,82)" "=CHISQ.INV(0.95,82)". so for this case the critical values are:

$\chi^2_{\alpha/2}=104.139$

$\chi^2_{1- \alpha/2}=62.132$

The confidence interval is given by:

$\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}$

$4.525 \leq \sigma^2 \leq 7.602$

Now we just take square root on both sides of the interval and we got:

$2.127 \leq \sigma \leq 2.757$

5 0

2 years ago