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Bumek [7]
2 years ago
9

I need help again.lol

Mathematics
1 answer:
Monica [59]2 years ago
8 0

Answer:

13\ units

Step-by-step explanation:

One is asked to find the distance between two points on a coordinate plane. The easiest way to do so is to use the distance formula, this formula is the following:

D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2

Where ((x_1,y_1)) and ((x_2,y_2)) are the points which one needs to find the distance between. In this case, these points are as follows:

k\ (-3,5)

j\ (-8, -7)

Substitute these points into the formula and solve for the distance between these points,

D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2

D=\sqrt{((-3)-(-8))^2+((5)-(-7))^2

Simplify,

D=\sqrt{((-3)-(-8))^2+((5)-(-7))^2

D=\sqrt{(-3+8)^2+(5+7)^2

D=\sqrt{(5)^2+(12)^2

D=\sqrt{25+144}

D=\sqrt{169}

D=13

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(w-2) (w+5) <br> I need help I don't understand ...
Phantasy [73]
<h3>Answer: w^2 + 3w - 10</h3>

===============================================

Work Shown:

Let x = w-2

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x(w+5)

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Now replace x with w-2 and distribute again

w(x) + 5(x)

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2 years ago
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Help guys plzzz asapppp
nignag [31]

sin(x) = opp/hyp
cos(x) = adj/hyp
tan(x) = opp/adj

sin(x) = 3.9/8.1
sin(x) = 0.481

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Each answer should be between 0 and 90 :)
4 0
2 years ago
Carla wants to start a college fund for her daughter Lila. She puts $63,000 into an account that grows at a rate of 2.55% per ye
Oksanka [162]

Answer:

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = 63000

r = 2.55% = 2.55/100 = 0.0255

n = 12 because it was compounded 12 times in a year.

Therefore, function, C(t), that represents the amount of money in the account t years after the account is opened is

C(t) = 63000(1 + 0.0255/12)^12t

C(t) = 63000(1.002125)^12t

For C(t) = 100000,

100000 = 63000(1.002125)^12t

100000/63000 = (1.002125)^12t

1.587 = 1.002125)^12t

Taking log of both sides

Log 1.587 = log 1.002125)^12t

Log 1.587 = 12tlog 1.002125)^

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5 0
3 years ago
What is the average rate of change for ƒ(x) = −2x + 70 over the interval 2 ≤ x ≤ 6?
Anvisha [2.4K]

Answer:

The average rate of change is -2

Step-by-step explanation:

we know that

To find out the average rate of change, we divide the change in the output value by the change in the input value.

In a linear function the average rate of change is a constant and is equal to the slope of the function

The linear function in slope intercept form is equal to

f(x)=mx+b

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b is the y-intercept or initial value of the linear function

In this problem we have

f(x)=-2x+70

so

m=-2\\b=70

therefore

The average rate of change is -2

4 0
3 years ago
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