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statuscvo [17]
3 years ago
8

What is the total cost of 0.5 pound of peaches selling for $0.80 per pound and 0.7 pound of oranges selling for $0.90 per pound?

5th grade work.
Mathematics
1 answer:
swat323 years ago
7 0
Given situation : 0.5 pound of peaches selling for 0.80 dollars/ pound 0.7 pound of oranges selling for 0.90 dollars / pound. Solution Given number 1 : Peaches => 0.5 pound = meaning, ½ pound is available, And 1 pound of it costs 0.80 dollars. Let’s solve: => 0.80 dollars * 0.5 => 0.40 dollars – the price of the peaches. Given number 2 : Oranges => 0.7 pounds of oranges, meaning less than 1 pound. And 1 pound costs 0.90 dollars Let’s solve to get the anwer => 0.7 * .90 => 0.63 dollars – the costs of 0.7 pounds of oranges,
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The rate at which a plant grows is constant. At the 3rd week it is 12 inches tall and at the 5th week it is 20 inches tall. If t
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3 years ago
Lou has an account with $10,000 which pays 6% interest compounded annually. If to that account, Lou deposits $5,000 at the begin
katovenus [111]

Answer:

Option d. $22154 is the right answer.

Step-by-step explanation:

To solve this question we will use the formula A=P(1+\frac{r}{n})^{nt}

In this formula A = amount after time t

                        P = principal amount

                        r = rate of interest

                       n = number of times interest gets compounded in a year

                        t = time

Now Lou has principal amount on the starting of first year = 10000+5000 = $15000

So for one year A=15000(1+\frac{\frac{6}{100}}{1})^{1\times1}

= 15000(1+.06)^{1}

= 15000(1.06) = $15900

After one year Lou added $5000 in this amount and we have to calculate the final amount he got

Now principal amount becomes $15900 + $ 5000 = $20900

Then putting the values again in the formula

A=20900(1+\frac{\frac{6}{100}}{1})^{1\times1}

= 20900(1+.06)^{1}

= 20900(1.06)=22154

So the final amount will be $22154.

3 0
3 years ago
PLEASE HELP!? Not that hard.
kobusy [5.1K]
Y = 4x - 1

// Plug this in for variable y in equation [1]

[1] 20x - 5•(4x-1) = 5
[1] 0 = 0 => Infinitely many solutions
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3 years ago
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